the 22 students bought a Valentine's presents they purchased 2 dozen for 22.95$ per and a box of chocolates for 13.45$ they spli
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In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°
The correct question in the attached figure
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio x:y is 25:18
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio x:y is 25:18