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3 years ago

2/3 (x – 7)= -2 i know x=4 but i need a good show of work for teacher worth 22 points make it worth it

Mathematics

1 answer:

Dafna1 [17]3 years ago

8 0

Step-by-step explanation:

⅔ (x – 7) = -2

Let's start by getting rid of the fraction. Multiply both sides by 3.

2 (x – 7) = -6

Distribute the 2:

2x – 14 = -6

Add 14 to both sides:

2x = 8

Divide both sides by 2:

x = 4

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Given: 1; -5; -13 ; -23 ; ...<br><br> Derive a formula for the nth term in the pattern.

mylen [45]

Answer:

f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

f(n) = an^2 +bn +c

Then we have ...

f(1) = 1 = a(1^2) +b(1) +c

f(2) = -5 = a(2^2) +b(2) +c

f(3) = -13 = a(3^2) +b(3) +c

Here's a way to solve these equations.

Subtract the first equation from the second:

-6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

-8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

-2 = 2a

a = -1

Then substituting into the 4th equation to find b, we have ...

-6 = 3(-1) +b

-3 = b

and ...

1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

5 = c

The formula is ...

f(n) = -n^2 -3n +5

3 0

4 years ago

What is a decimal in mathematics?

inn [45]

A decimal is 3.5, or 2.4739464. a number and a little bit. basically not a whole number. :)

5 0

4 years ago

Anyone know this if so please help

Likurg_2 [28]

24. 9×4=36 4×-3=12 so 36+(-12)=24

7 0

4 years ago

Read 2 more answers

Uranus moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 2,876,769,540 k

Alina [70]

Answer:

The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

Step-by-step explanation:

Consider the provided information.

The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.

The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).

$e=\frac{c}{a}$

Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.

$0.0444=\frac{c}{2,876,769,540 }$

$c=127728567.576$

Minimum distance of Uranus from the sun is:

$a-c=2,876,769,540-127728567.576\\a-c=2749040972.424\approx2749040972$

Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

6 0

3 years ago

Graph x ≤ 5 on the number line.

dalvyx [7]

Answer:

whole circle on the 5, arrow facing the left

8 0

2 years ago