<span>1. multiply to -18
add to -17 = Multiplying -18 and 1 will give -18 as the result and then on
adding -18 and + 1 the result comes to -17
</span><span>2. multiply to 36 add
to -13 = Multiplying -9 and -4 will give -36 as the result and then on
adding -9 and -4 the result comes to -13
</span><span>3. multiply to -24 add to -5<span>= </span></span><span>Multiplying -8 and +3 will give -24 as the result and then on
adding -8 and +3 the result comes to -5
4. multiply to -18 add to 7= </span><span>Multiplying +9 and -2 will give -18 as the result and then on
adding +9 and -2 the result comes to 7
5. multiply to -36 add to 9= </span><span><span>Multiplying +12 and -3 will give -36 as the result and then on
adding +12 and -3 the result comes to 9
</span> 6. multiply to 24 add to 10= </span><span><span>Multiplying +6 and +4 will give 24 as the result and then on
adding +6 and +4 the result comes to 10
</span> 7. multiply to 18 add to -9= </span><span><span><span>Multiplying -6 and -3 will give -18 as the result and then on
adding -6 and -3 the result comes to -9
</span> 8. multiply to -36 add to -16</span>= </span><span>Multiplying -18 and +2 will give -36 as the result and then on
adding -18 and +2 the result comes to -16</span>
Answer:
0.83
Step-by-step explanation:
T chart but thats all i can think of
Answer:
Only 97 is the one that's prime. The answer to the riddle is 97, so check if 79 is "ones digit is two less than my tens digit".
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Answer:
We accept H₀ , we do not have enought evidence for rejecting H₀
Step-by-step explanation:
Normal Distribution
sample size n = 60
standard deviation σ = 15
1.Hypothesis Test : Is a one tailed-test on the right
H₀ null hypothesis μ₀ = 50
Hₐ alternative hypothesis μ₀ > 50
2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence
then z(c) = 2.32
3.- We compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15
z(s) = 15.49/15 ⇒ z(s) = 1.033
4.- We compare values of z(c) and z(s)
z(s) < z(c) 1.033 < 2.32
z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀