The graph<span> of an </span>inequality in two variables<span> is the set of points that represents all solutions to the </span>inequality<span>.
A </span>linear inequality<span> divides the coordinate plane into </span>two <span>halves by a boundary line where one half represents the solutions of the </span>inequality. The boundary line is dashed for > and < and solid for ≤ and ≥.<span>A way to solve a linear system algebraically is to use the substitution method.
</span>The graphs of equations<span> within a </span>system<span> can </span>tell<span> us how </span>many solutions<span> exist for </span>Infinite Solutions<span>. </span>If <span>the graphs of the </span>equations<span> intersect, then there is </span>one solution<span> that is true for Looking at the graph does </span>not tell<span> us exactly where that point is, but we don't So a </span>system<span> made of two intersecting lines </span>has one solution.
Two equations that have the same solution are called equivalent<span> equations e.g. The addition </span>property<span> of equality tells us that adding the same number to. We can also </span>use<span> this example with the pieces of wood to explain the </span><span>are </span>equal<span> as well.</span>
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer:
The first table
Step-by-step explanation:
You have to make sure that x is unique throughout.
First Table: the inputs are 2, 4, 6, 7
each input value is different or unique
Second Table: input values are 3, 5, 3, 5
three and five repeat themselves, so there is not a function
Third Table: input values are -2, 0, 1, -2
negative 2 repeats itself so it is not unique
To find X, we can divide 5 into 40.
40 divided by 5 is 8.
Now we can do 5 x 8. That is 40.
X=40
OR we can do it another way.
40 divided by 5 is 8.
Cross out 5 divided by 5.
Now we have 8. Still.
X is 8
18+36=54
i tried to do all of these and none of them add up to 54