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3 years ago

How to Identify Newtons Three Laws in my Own Words?

Physics

1 answer:

ipn [44]3 years ago

5 0

I understand the struggle. Here's a way to do it.

Identify Newton's Three Laws, and let it be important that you understand what you're reading. If there's a passage, read the passage/text and look for any important detail you should add to your piece, and add any information you have learned from the passage/text and put it into your own words. You should make sure that the information you've written down is consistent with the passage/text and that your phrasing is not too close to the original.

-I anticipate that this would help you.

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What is the atmospheric pressure 1.00 km above the surface of Venus? Express your answer in Earth-atmospheres.

EleoNora [17]

Below is an attachment containing the solution.

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3 years ago

A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.6 A runs through the wire

lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F $_{mg}^>$ | = I( $B^>$ × $L^>$ )

given that

I = 2.6 A

$B^>$ = 0.17

$L^>$ = 0.52

so we substitute

|F $_{mg}^>$ | = 2.6( 0.17i" × 0.52j" )

|F $_{mg}^>$ | = 0.2298 N

Therefore, the magnitude of the magnetic force on the wire is 0.2298 N

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3 years ago

Can Someone please help me! <br><br> What is deposition

7nadin3 [17]

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3 years ago

Read 2 more answers

A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to