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xz_007 [3.2K]
3 years ago
9

Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such

a sound wave? (b) If the speed of sound in tissue is 1650 m/s, what is the wavelength of this wave in tissue? (Take the speed of sound in air to be 343 m/s.)
Physics
1 answer:
maxonik [38]3 years ago
7 0

Explanation:

It is given that,

Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz

The speed of the sound in air, v = 343 m/s

(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

\lambda_1=\dfrac{343\ m/s}{3820\ Hz}

\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}

\lambda_2=0.43\ m

Hence, this is the required solution.

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A tube with sealed ends has some sand at one end. When the tube is turned upside down the sand falls 0.6m then settles down agai
barxatty [35]

Answer:

2.943 J

Explanation:

Data:

acceleration due to gravity, g = 9.81 m/s²

mass of sand  = 0.5 kg

distance  = 0.6

Thermal energy  = the energy possessed by the falling sand

The force of sand = ma

                              = 0.5 * 9.81\\= 4.905 N

However, the energy is given as the force multiplied by the distance, so

E =fd

   4.905 * 0.6\\= 2.943 J

Therefore, the thermal energy is 2.943 joules

 

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2 years ago
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A tennis ball is tossed upward with a speed of 3.0 m/s. We can ignore air resistance. What is the velocity of the ball .40 secon
alexira [117]

Answer:

<em>Hello, The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).</em>

Explanation:

The equation for the velocity of an object thrown upward is the following:

v = v0 + g · t

Where:

v = velocity of the ball.

v0 = initial velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:

v = v0 + g · t

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<em>Hope That Helps!</em>

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2 years ago
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A ball is launched at an angle of 10 degrees from a 20 meter tall building with a speed of 4 m/s. How long is the ball in the ai
shutvik [7]

Answer:

d) None of the above

Explanation:

v_{o} = inituial velocity of launch = 4 m/s

θ = angle of launch = 10 deg

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

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t = time of travel

using the equation

y=v_{oy} t+(0.5)a_{y} t^{2}

- 20 = (0.695) t + (0.5) (- 9.8) t²

t = 2.1 sec

consider the motion along the horizontal direction

x = horizontal displacement

v_{ox} = initial velocity along horizontal direction = 4 Cos10 = 3.94 m/s

a_{x} = acceleration along the horizontal direction = 0 m/s²

t = time of travel =  2.1 s

Using the kinematics equation

x =v_{ox} t+(0.5)a_{x} t^{2}

x = (3.94) (2.1) + (0.5) (0) (2.1)²

x = 8.3 m

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y_{o} =initial vertical position at the time of launch = 20 m  

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v_{fy} = final velocity along vertical direction at highest point = 0 m/s

using the equation

{v_{fy}}^{2}= {v_{oy}}^{2} + 2 a_{y}(y - y_{o})

0^{2}= 0.695^{2} + 2 (- 9.8)(y - 20)

y = 20.02 m

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h = y - y_{o}

h = 20.02 - 20

h = 0.02 m

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KiRa [710]

Answer:

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Explanation:

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The coffee dough left in the cup after evaporation is

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Since coffee is essentially water, let's use the specific heat of water,

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Let's calculate

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     T_{f} = 85.7 ° C

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