While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
1 answer:
<h2>18.6467 N</h2>
Explanation:
The Work done by any force is defined as the force applied times the displacement of point of application of force in the direction of force.
This is better represented as a scalar product of Force vector and displacement vector.
Here, the angle between force and displacement is .
∴ Magnitude of force =
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The position of an oscillating mass is given by:
where A is the amplitude of the oscillation, the angular frequency and t the time.
The velocity of the oscillating mass can be found by calculating the derivative of the position:
In this problem, A=2.0 cm and , so if we substitute these data and t=0.4 s we can find the velocity at t=0.4 s:
Answer:
Its speed is maximum and its acceleration is zero
Explanation:
- Concerning the speed:
In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:
where k is the spring constant, x is the displacement, m is the mass and v is the speed.
We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.
- Concerning the acceleration:
According to Newton's second law, the acceleration of the system is proportional to the net force:
the net force is just the restoring force of the spring, given by Hooke's law:
So, the acceleration is
and we see that when the displacement is zero, x = 0, and so the acceleration is also zero.