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3 years ago

Given a triangle with a =14 A = 41 and B = 34, what is the length of c? Round to the nearest tenth

Mathematics

2 answers:

slavikrds [6]3 years ago

6 0

Answer:

20.6°

Step-by-step explanation:

Given in a triangle

a = 14 ∠A = 41° and ∠B = 34°

Then we have to find the measure of side c

Since sum of all angles of a triangle is 180°

So ∠A + ∠B + ∠C = 180°

41° + 34° + ∠C = 180°

75° + ∠C = 180°

∠C = 180 - 75

= 105°

Now from sine rule,

$\frac{a}{SinA}= \frac{c}{SinC}$

$\frac{14}{Sin(41)}= \frac{c}{Sin(105)}$

$c=\frac{14\times Sin(105)}{Sin(41)}$

$c=\frac{14\times 0.9659}{0.6561}$

= 20.61°

≈ 20.6°

makkiz [27]3 years ago

3 0

Your answer is 20.6

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Harlamova29_29 [7]

$y = \frac 14x^2$ is less steep than the parent quadratic equation, while $y = 2x^2$ is steeper than the parent quadratic equation

<h3>How to determine the equations</h3>

The parent equation of a quadratic equation is represented as:

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For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k

So, we have:

$y = (kx)^2$

If k is greater than 1, then the function would be steeper; else, the function would be less steep.

Assume k = 2, we have:

$y = (2x)^2$

$y = 2x^2$

Assume k = 1/2, we have:

$y = (\frac 12x)^2$

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Hence, $y = \frac 14x^2$ is less steep than the parent quadratic equation, while $y = 2x^2$ is steeper than the parent quadratic equation

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2 years ago

Someone help pls :((

harina [27]

Answer:

56.714°

Step-by-step explanation:

Since we do not have a full angle of this proposed triangle, we must do this by splitting it into two right triangles instead of using the law of sines.

250m*sin(40°) = 250m*0.64278760968 = 160.696902422m

452.4m-160.696902422m=291.703097578m

Use pythagorean theorem:

$\sqrt{250^2 - 160.696902422^2}$

62500-25823.494448025787=36676.505552

$\sqrt{36676.505551974216}$ = 191.511110779m

arctan(291.703097578m/191.511110779m)≈56.714°

6 0

3 years ago

a starting lineup in a basketball consists of two guards, two forwards, and a center. a. a certain college team has on its roste

AURORKA [14]

Different starting lineups can be created - 120+60+120=300. A certain college team has on its roster 4 centers, 5 guards, 5 forwards, and one individual (x) who can play either guard or forward.

1. A lineup without x is an example. You must decide.

5 quards, 2 guards;

two of the three forwards;
from 4 centers, 1 center.

It can be made as -

2C5 × 2C3× 1C4 = 10× 3×4 = 120 ways

2. Consider starting lineups with guard x. You must decide.

2 guards chosen from 6 quards (at least one of them must be x);

two of the three forwards;
from 4 centers, 1 center.

1C5×2C3×1C4 = 5×3×4 = 60 ways

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2C5×1C3×1C4 = 10×3×4 = 120 ways.

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1 year ago

2+2+374+820+829-9204

dimulka [17.4K]

Answer:

Step-by-step explanation:

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3 years ago

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4 0

3 years ago