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melisa1 [442]
3 years ago
12

Given a triangle with a =14 A = 41 and B = 34, what is the length of c? Round to the nearest tenth

Mathematics
2 answers:
slavikrds [6]3 years ago
6 0

Answer:

20.6°

Step-by-step explanation:

Given in a triangle

a = 14 ∠A = 41° and ∠B = 34°

Then we have to find the measure of side c

Since sum of all angles of a triangle is 180°

So   ∠A + ∠B + ∠C = 180°

       41° +  34° + ∠C = 180°

        75° + ∠C = 180°

         ∠C = 180 - 75

               = 105°

Now from sine rule,

\frac{a}{SinA}= \frac{c}{SinC}

\frac{14}{Sin(41)}= \frac{c}{Sin(105)}

c=\frac{14\times Sin(105)}{Sin(41)}

c=\frac{14\times 0.9659}{0.6561}

= 20.61°

≈ 20.6°

makkiz [27]3 years ago
3 0
Your answer is 20.6
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Harlamova29_29 [7]

y = \frac 14x^2 is less steep than the parent quadratic equation, while y = 2x^2 is steeper than the parent quadratic equation

<h3>How to determine the equations</h3>

The parent equation of a quadratic equation is represented as:

y = x^2

For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k

So, we have:

y = (kx)^2

If k is greater than 1, then the function would be steeper; else, the function would be less steep.

Assume k = 2, we have:

y = (2x)^2

y = 2x^2

Assume k = 1/2, we have:

y = (\frac 12x)^2

y = \frac 14x^2

Hence, y = \frac 14x^2 is less steep than the parent quadratic equation, while y = 2x^2 is steeper than the parent quadratic equation

Read more about quadratic equations at:

brainly.com/question/11631534

8 0
2 years ago
Someone help pls :((
harina [27]

Answer:

56.714°

Step-by-step explanation:

Since we do not have a full angle of this proposed triangle, we must do this by splitting it into two right triangles instead of using the law of sines.

250m*sin(40°) = 250m*0.64278760968 = 160.696902422m

452.4m-160.696902422m=291.703097578m

Use pythagorean theorem:

\sqrt{250^2 - 160.696902422^2}

62500-25823.494448025787=36676.505552

\sqrt{36676.505551974216} = 191.511110779m

arctan(291.703097578m/191.511110779m)≈56.714°

6 0
3 years ago
a starting lineup in a basketball consists of two guards, two forwards, and a center. a. a certain college team has on its roste
AURORKA [14]

Different starting lineups can be created - 120+60+120=300. A certain college team has on its roster 4 centers, 5 guards, 5 forwards, and one individual (x) who can play either guard or forward.

1. A lineup without x is an example. You must decide.

  • 5 quards, 2 guards;
  • two of the three forwards;
  • from 4 centers, 1 center.

It can be made as -

2C5 × 2C3× 1C4 = 10× 3×4 = 120 ways

2. Consider starting lineups with guard x. You must decide.

  • 2 guards chosen from 6 quards (at least one of them must be x);
  • two of the three forwards;
  • from 4 centers, 1 center.

1C5×2C3×1C4 = 5×3×4 = 60 ways

3. Think about lineups where x is the forward. You must decide.

  • 5 quards, 2 guards;
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  • from 4 centers, 1 center.

2C5×1C3×1C4 = 10×3×4 = 120 ways.

Therefore, total number different lineups is - 120+60+120=300.

To learn more about combinations from given link

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3 0
1 year ago
2+2+374+820+829-9204
dimulka [17.4K]

Answer:

Step-by-step explanation:

2+2+374+820+829-9204

4+374+820+829-9204

378+820+829-9204

1198+829-9204

2027-9204

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5 0
3 years ago
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30. you can model this with an equation and solve, x being the smallest number and the x+1 and x+2 representing the consecutive numbers.

x+(x+1)+(x+2)=93
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30+31+32=93
4 0
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