is less steep than the parent quadratic equation, while
is steeper than the parent quadratic equation
<h3>How to determine the equations</h3>
The parent equation of a quadratic equation is represented as:

For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k
So, we have:

If k is greater than 1, then the function would be steeper; else, the function would be less steep.
Assume k = 2, we have:


Assume k = 1/2, we have:


Hence,
is less steep than the parent quadratic equation, while
is steeper than the parent quadratic equation
Read more about quadratic equations at:
brainly.com/question/11631534
Answer:
56.714°
Step-by-step explanation:
Since we do not have a full angle of this proposed triangle, we must do this by splitting it into two right triangles instead of using the law of sines.
250m*sin(40°) = 250m*0.64278760968 = 160.696902422m
452.4m-160.696902422m=291.703097578m
Use pythagorean theorem:

62500-25823.494448025787=36676.505552
= 191.511110779m
arctan(291.703097578m/191.511110779m)≈56.714°
Different starting lineups can be created - 120+60+120=300. A certain college team has on its roster 4 centers, 5 guards, 5 forwards, and one individual (x) who can play either guard or forward.
1. A lineup without x is an example. You must decide.
- two of the three forwards;
- from 4 centers, 1 center.
It can be made as -
2C5 × 2C3× 1C4 = 10× 3×4 = 120 ways
2. Consider starting lineups with guard x. You must decide.
- 2 guards chosen from 6 quards (at least one of them must be x);
- two of the three forwards;
- from 4 centers, 1 center.
1C5×2C3×1C4 = 5×3×4 = 60 ways
3. Think about lineups where x is the forward. You must decide.
- 5 quards, 2 guards;
- 2 forwards from 4 forwards (x must be one of them);
- from 4 centers, 1 center.
2C5×1C3×1C4 = 10×3×4 = 120 ways.
Therefore, total number different lineups is - 120+60+120=300.
To learn more about combinations from given link
brainly.com/question/8781187
#SPJ4
Answer:
Step-by-step explanation:
2+2+374+820+829-9204
4+374+820+829-9204
378+820+829-9204
1198+829-9204
2027-9204
-7177
30. you can model this with an equation and solve, x being the smallest number and the x+1 and x+2 representing the consecutive numbers.
x+(x+1)+(x+2)=93
3x+3=93
3x=90
x=30
x+1=31
x+2=32
30+31+32=93