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katrin2010 [14]
3 years ago
13

if a parabola is horizontally translated 15 units left, stretch by a factor of 20, vertically translated down 30 units and refle

cted in the x axis determine the equation of the parabola in vertex form
Mathematics
2 answers:
Setler [38]3 years ago
5 0
Your normal parabola is y=x^2 but with translations you get the form y=a(x-h)^2+k. it is horizontally shifted by 15 so h=15, the stretch factor is 20 so a=20, it is translated down by 30 so k=-30, and it is reflected in the x axis so a is negative. your answer is y=-20(x-15)^2-30. DONT OPEN ANY SKETCHY LINKS!!!
melamori03 [73]3 years ago
5 0

Answer:

y' = a(x'- ((h-15)/20))² + -(k-30)

Step-by-step explanation:

Vertex: (h,k)

horizontally translated 15 units left: (h-15 , k)

stretch by a factor of 20: ((h-15)/20 , k)

vertically translated down 30 units: ((h-15)/20 , k-30)

reflected in the x axis: ((h-15)/20 , -(k-30))

Vertex' (h' , k'): ((h-15)/20 , -(k-30))

Equation: y' = a(x'-h')² + k'

y' = a(x'- ((h-15)/20))² + -(k-30)

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Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
3 years ago
Hacksaw’s Boats of St. Lucia takes tourists on a daily whale/dolphinwatch cruise. Their brochure claims an 80% chance of siting
Fittoniya [83]

Answer:

The probability you see a dolphin or a whale on both days is 0.64

Step-by-step explanation:

Consider the provided information.

It is given that the brochure claims an 80% chance of siting a dolphin or a whale.

The provided claims can be written as: 80% or 0.80

Let say first day you see a dolphin or a whale and same happen on the next day.

Thus, the probability is:

0.80 × 0.80 = 0.64

Probability of see them on both days is 0.64

Hence, the probability you see a dolphin or a whale on both days is 0.64

5 0
3 years ago
Does exposure to classical music (through instrument lessons or concert attendance) improve children's scholastic performance? I
Anestetic [448]
The explanatory variable is the amount of exposure the student is given to classical music.
6 0
3 years ago
Simplify X 1/2 times X 2/3
vovikov84 [41]

Answer:

3/6x • 4/6x

12/6x

2x

Step-by-step explanation:

you would change both fractions to have the same denominator then simplify if needed

5 0
3 years ago
The surface area of yringaler prism​
Trava [24]

Answer:

180 cm

Step-by-step explanation:

2(3*10) = 60

3*12 = 24

1/2(12*8) * 2 = 96

formula for a triangle is 1/2 b h

7 0
3 years ago
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