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3 years ago

PLEASE SOMEONE, I NEED TO PASS !

Mathematics

2 answers:

amid [387]3 years ago

6 0

Have you tried class notes? Or studying? Attempt that, it will help in the future more to understand it than to look it up. e_e'

algol133 years ago

5 0

C. I hope this helps!

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What is the not number in this sequence?

Oksanka [162]

The answer is: "123454321"
Hope this helps!

8 0

2 years ago

Simplify -3+3(8x+4)

Zarrin [17]

Answer:

24x+9

Step-by-step explanation:

Simplify the expression.

24x+9

7 0

2 years ago

Read 2 more answers

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago

Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?

Shtirlitz [24]

The equation that has the solution $x = \frac{5 \pm \sqrt{7}}{3}$ is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

$x = \frac{5 \pm \sqrt{7}}{3}$

The solution to a quadratic equation is

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b = -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution $x = \frac{5 \pm \sqrt{7}}{3}$ is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0

1 year ago

Ten thousand raffle tickets are sold. one first prize of$2000,4 second prizes of $800 each, and10 third prizes of$400 each are t

Makovka662 [10]

From the information given:
Random wins 2000 800 400 0
Probabilities 1/10^4 4/10^4 10/10^4 9985/10^4
thus the expectation will be:
E(x)=[2000+4*800+4000+9985*0]/10^4
E(x)=9200/10000
E(x)=$0.92

3 0

3 years ago