<u>Answer:</u>
He must sell 190 posters make a profit of $300.
<u>Explanation: </u>
Given:
Base fee= $270
Fee for supplies= $2
Cost of poster=$5
To find:
The number of posters to be sold to get a profit of $300=?
Solution:
Let the number of posters sold be n.
Now, we know that,
profit = selling price – cost price
$ 300 = $ 5 for each poster – ( $ 270 base fee + $ 2 for each poster)
300 = 5 x n – (270 + 2 x n)
300 = 5n – 270 – 2n
5n – 2n = 300 + 270
3n = 570
n = 190
9514 1404 393
Answer:
slope = 1
Step-by-step explanation:
In the attachment, we have shown rise and run as 3 units each. The segments could be drawn 1 unit long. In any event, the ratio is the slope:
slope = rise/run = 3/3
slope = 1
_____
It is most convenient to draw the rise and run segments from/to places where the line crosses grid intersections. Often, but not always, the y-intercept will be such a point. Then you can look for the nearest grid crossing for figuring rise and run.
Here, the y-intercept is (0, 1), and the closest grid crossing to the right is (1, 2). The rise is 2-1 = 1, and the run is 1-0 = 1. The ratio is 1/1 = 1, same as above. The ratio of rise to run will be the same everywhere for a straight line.
