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VashaNatasha [74]
3 years ago
8

What is the value of x when -25(x - 4) = -55(x - 10) ?

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
5 0

Simplify both sides of the equation

-25(x-4)=-55(x-10)

(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)

Distribute

-25x+100=-55x+550

Add 55x  to both sides

-25x+100+55x=-55x+550+55x

30x+100-100=550-100

subtract 100 from both sides

30x+100-100=550-100

30x=450

divide both sides by 30

30x/30=450/30

x= 15

The value of x is 15


I hope that's help you my friend !

MA_775_DIABLO [31]3 years ago
5 0

Answer:

x=15

Step-by-step explanation:

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Coby sells apples and bananas at his fruit store. He charges $6 for a bunch of bananas, and $8 for a pound of apples. If a custo
Over [174]

Answer:

  • 6 bunches of bananas
  • 7 pounds of apples

Step-by-step explanation:

We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.

Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...

  6B +8(13 -B) = 92

  -2B + 104 = 92 . . . . . eliminate parentheses

  B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B

  13-B = 7 . . . . . . . . . . . the number of pounds of apples

The customer bought 6 bunches of bananas and 7 pounds of apples.

_____

<em>Comment on the solution</em>

You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.

6 0
3 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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