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2 years ago

What is the remainder when () = 3 − 11 − 10 is divided by x+3

Mathematics

1 answer:

ziro4ka [17]2 years ago

7 0

Answer:

-18/x+3

Step-by-step explanation:

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PLZ HELP ASAP!!!!! I NEED IT BADLY!!!!!

Ludmilka [50]

131/5 divided by 11/1
to divide by fractions, you multiply by the reciprocal and the reciprocal of 11/1 is 1/11...
131/5•1/11 and you just multiply across so the answer is every 131/55 miles. if you want it as a mixed number, it's 2 21/55

4 0

3 years ago

A number has the same digit in its hundreds place and its hundredths place.

Yuki888 [10]

Answer:

One is 2 0's before the decimal point (100) and the other is 2 decimal places AFTER the decimal point (0.01)

Essentially, the question is asking us how many times do we multiply 0.01 to get 100? This will be how many times greater 100 is compared to 0.01

Lets move the decimal point 4 times to the right:

0.01

00.1

1.0

10.0

100.0

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP AND BE CORRECT

Sergio [31]

(b⁷/4⁵)⁻³

= (4⁵/b⁷)³

= 4¹⁵/b²¹

Therefore answer is option b

Must click thanks and mark brainliest

3 0

3 years ago

Yesterday, 20 guests at a hotel called for room service, and 60 guests did not call for room service. What percentage of the gue

Neko [114]

33.3% is the answer, I think

20/60 ---> 1/3, covert this to a percentage and it equals 33.3%

6 0

2 years ago

A random sample of 64 observations produced a mean value of 84 and standard deviation of 5.5. The 90% confidence interval for th

ASHA 777 [7]

Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

Step-by-step explanation:

When population standard deviation is not given ,The confidence interval population proportion is given by ( $\mu$ ):-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where n= Sample size.

s= Sample standard deviation

$\overline{x}$ = sample mean

t* = Critical t-value (Two-tailed)

As per given , we have

$\overline{x}=84$

n= 64

Degree of freedom : df = n-1=63

s= 5.5

Significance level : $\alpha=1-0.90=0.1$

Two-tailed T-value for df = 63 and $\alpha=1-0.90=0.1$ would be

$t_{\alpha/2,df}=t_{0.05,63}=1.669$ (By t-distribution table)

i.e. t*= 1.669

The 90% confidence interval for the population mean μ would be

$84\pm (1.669)\dfrac{5.5}{\sqrt{64}}$

$=84\pm (1.669)\dfrac{5.5}{8}$

$\approx84\pm 1.15$

$=(84-1.15,\ 84+1.15)=(82.85,\ 85.15)$

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

6 0

3 years ago