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3 years ago

Which situation represents a propertional relationship between the hours worked and the amount earned fir matt and jane?

Mathematics

1 answer:

mafiozo [28]3 years ago

6 0

I say girl why are you calling and math Is easy if you think about it it’s really cool

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What is the following number in decimal form?1.68 × 10^8 =?

Furkat [3]

Hello,

Shall we begin?

=1.68 X 10^8
=1.68 x 100,000,000
= 168,000,000

<span>Answers: 168,000,000</span>

3 0

3 years ago

A music competition on television had five elimination rounds. After each elimination, only half of the contestants were sent to

guajiro [1.7K]

There would have to be a total of 32 contestants at the start of the show,
next round there were only 16
next 8
then 4
and the final round would have had 2 contestants trying to win

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3 years ago

PLEASE ANSWER ASAP AND CORRECTLY FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!

Kobotan [32]

Answer:16.63 meters

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Determine whether the biconditional is a true statement.<br><br> |x|=9 if and only if x=9

Charra [1.4K]

Answer:

the biconditional is a true statement

Step-by-step explanation:

The absolute value of x is 9 if it's equal to 9.

(If this is wrong I'm sorry I haven't done this kind of math in a while!)

8 0

4 years ago

In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu

Leya [2.2K]

Explanation:

The equation of comet E is given below as

$\frac{(y+16)^2}{400}+\frac{x^2}{144}=1$

The equation of comet H is modelled below as

$\frac{(y+13)^2}{144}-\frac{x^2}{25}=1$

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

$\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}$

Whise center is

$\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}$

By comparing coefficient, we will have

$\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}$

Hence,

The vertex of comet E will be

$\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}$

The vertex of comet E is

$(12,0),(-12,0)$

Part C:

It is the foci forboth comets

$\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\ \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}$

Hence,

The foci will be

$\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}$

5 0

1 year ago