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stellarik [79]
3 years ago
8

particles of mass 2m and m are fixed at the extreme of a light string of lenght l.find the centre of mass and the moment of iner

tia of the system of particles from the lighter particle.
Mathematics
1 answer:
Sever21 [200]3 years ago
3 0
Centre of mass will be at a distance of (L / 3) from mass 2m.

moment of inertia = m(2L/3)^2 + (2m)(L/3)^2
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Answer:

The equation's result: 32,000 (Rounded)

Goal: Find the closest or equivalent result in another expression

Step-by-step explanation:

<h3>A)</h3>

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How we got to 31,636 was by dividing from left to right.

Remember: When dividing decimals, it's like multiplying whole numbers in a way. The number(the quotient, also) ends up bigger instead of being smaller like when dividing whole numbers. If you multiply decimals, they(the product) end up smaller.

Therefore, A is the correct answer.

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