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stellarik [79]
3 years ago
8

particles of mass 2m and m are fixed at the extreme of a light string of lenght l.find the centre of mass and the moment of iner

tia of the system of particles from the lighter particle.
Mathematics
1 answer:
Sever21 [200]3 years ago
3 0
Centre of mass will be at a distance of (L / 3) from mass 2m.

moment of inertia = m(2L/3)^2 + (2m)(L/3)^2
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Algebra II<br>Which is the correct statement?
Nataly_w [17]
B. g(x) is translated 2 units left. it's inside so it's a horizontal translation, and it's +2 which means it's translated left
6 0
3 years ago
Help me answer this question.
neonofarm [45]

Answer:

<h2>8 units²</h2>

Step-by-step explanation:

Let side of the square = a

The , Area of square = a²

Now, Midpoint of Diagonal DB is E

And DE = 2 units

So, DB = 2 DE = 2 × 2 = 4 units

Now, using Pythagoras theorem in ∆ BCD

DB² = DC² + BC²

plug the values

{4}^{2}  =  {a}^{2}  +  {a}^{2}

Collect like terms

{4}^{2}  = 2 {a}^{2}

Evaluate the power

16 = 2 {a}^{2}

Swipe the side of the equation

2 {a}^{2}  = 16

Divide both sides of the equation by 2

\frac{2 {a}^{2} }{ 2 }  =  \frac{16}{2}

Calculate

{a}^{2}  = 8

Therefore, The area of the square is 8 sq.units.

Hope this helps..

Best regards!!

3 0
3 years ago
Find an equation of the line described below. Write the equation is slope-intercept from ( solved for y), when possible. Through
Sladkaya [172]

Answer:

The equation of the line that is passing through the point (5,4) and is parallel to x-axis would be y=4

Step-by-step explanation:

Given that the line passes through the point (5,4).

As the line is parallel to the x-axis, the slope of the line would be zero.

And we have point (5,4) from which the line is passing.

So, x_1=5\  ,\ y_1=4\ and\ m=0

The equation of the line passing through point (x_1,y_1) is

y-y_1=m(x-x_1)\\y-4=0(x-5)\\y-4=0\\y=4

So, the equation of the line that is passing through the point (5,4) and is parallel to x-axis would be y=4

4 0
3 years ago
How does the graph of y=-3√2x-4 compare to the graph of y=-3√x-4?
kifflom [539]
<span>Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:

</span><span>The graph is compressed horizontally by a factor of 2
x=1/2x'
</span>y=-3(√2x)-4 
y=-3(√x')-4 <span>

</span><span>moved left 4
x=x'-4
</span>y=-3(√x)-4 
y=-3(√x'-4)-4 
<span>
moved down 4
y=y'-4
</span>y=-3(√x-4)-4 
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Answer: C. <span>The graph is compressed horizontally by a factor of 2, moved left 4, and moved down 4.
</span>
6 0
3 years ago
Read 2 more answers
What’s the correct answer for this?
sammy [17]

Answer:

(0,2)

Step-by-step explanation:

2:4 means one part is 2/(2+4)=1/3 of AB and the other part is 2/3 of AB

Add 1/3 of the distance from -2 to 4. (1/3)(4+2)=2. -2+2=0 The x coordinate is 0

Subtract 1/3 of the distance from 6 to -6, (1/3)6+6)=4 6-4=2 The y coordinate is 2

The point is (0,2)

3 0
3 years ago
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