Answer:
<h3>#1</h3>
<u>Trapezoid</u>
- A = (b₁ + b₂)h/2
- A = (4.8 yd + 29.4 ft)(8 yd)/2 = (14.6 yd)(4 yd) = 58.4 yd²
<h3>#2</h3>
<u>Rectangle</u>
- A = ab
- A = 2 yd * 3.1 yd = 6.2 yd²
<h3>#3</h3>
<u>Equilateral triangle</u>
- A = √3/4a²
- A = √3/4(10²) = 25√3
<h3>#4</h3>
<u>Regular octagon</u>
- A = aP/2
- A = 14.5(12*8)/2 = 696
Answer: Yes, B
Step-by-step explanation:
B because every x-value corresponds to exactly one y value.
Answer:
Step-by-step explanation:
1) This Stem and Leaf plot works like a Histogram. Completing the question, check below the Stem plot. Look the data out of the Stem plot and within (in the graph below)
32, 34
, 38
, 39
, 39
, 40
, 43
, 45
, 46
, 49
, 53
, 54
, 57
, 58
, 59
, 59
, 63
, 68
2) Notice how the first digit is on the Stem column (check below)
3) To find the first and Third Quartiles
Let's use the formulas to find the position, then the value. As it follows:
Answer:
a = 4,
b = 12
c = 10
d = 15
Step-by-step explanation:
Since the product of each column is equal, therefore,
b*5 = 60
b = 60 ÷ 5 = 12
c*6 = 60
c = 60 ÷ 6 = 10
Since the sum of each column are equal, therefore,
12 + 10 + a = 5 + 6 + d
22 + a = 11 + d
Think of a number you can add to 22, and another number you can add to 11, which will make both sides equal. Add both numbers, whenmultiplied together should give you 60.
Factors of 60 are:
(a, d)
(1, 60) => 22 + a = 11 + d => 22+1 = 11+60 (incorrect)
(2, 30) => 22 + a = 11 + d => 22+2 = 11+30 (incorrect)
(3, 20) => 22 + a = 11 + d => 22+3 = 21+20 (incorrect)
(4, 15) => 22 + a = 11 + d => 22+4 = 11+15 => 26 = 26 [CORRECT]
(5, 12) => 22 + a = 11 + d => 22+5 = 11+12 (incorrect)
(6, 10) => 22 + a = 11 + d => 22+6 = 11+10 (incorrect)
Therefore,
a = 4,
d = 15
Answer:
The difference quotient for 
is 
.
Step-by-step explanation:
The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by
So, for the function the difference quotient is:
To find 
, plug 
instead of 
Finally,
The difference quotient for is .
