Answer:
150.72
Step-by-step explanation:
Answer:
Step-by-step explanation:
We would apply the formula for exponential decay which is expressed as
A = P(1 - r/n)^ nt
Where
A represents the value after t years.
n represents the period for which the decrease in value is calculated
t represents the number of years.
P represents the value population.
r represents rate of decrease.
From the information given,
P = 23000
r = 8% = 8/100 = 0.08
n = 1
Therefore, the exponential decay function described in this situation is
A = 23000(1 - 0.08/n)1)^ 1 × t
A = 23000(0.92)^t
If A = 15000, then
15000 = 23000(0.92)^t
0.92^t = 15000/23000 = 0.6522
Taking log of both sides to base 10
Log 0.92^t = log 0.6522
tlog 0.92 = log 0.6522
- 0.036t = - 0.1856
t = - 0.1856/- 0.036
t = 5 years to the nearest year
Here, Your Expression: y = 0.25 (2^x)
So, we can see the expression is "Exponential" which increases double in every hour. So, the only graph with that pattern is 3rd one.You can compare following coordinates: (1, 50), (2, 100), (3, 200)
For every 1 value of x, y increases to it's double.
In short, Your Answer would be Option C
Hope this helps!
Answer is “D” I took the test my self
Answer:
np>10 and n(1-p)>10
Step-by-step explanation:
- Appropriate notation the Large Counts Condition for Normality is
- The Large Counts Condition for Normality states that is the number of successes and failures which should be above the 10 to be assume normality
- that is here express as n(p)>10 and n(1-p)>10
- This is the notation of the Large Counts Condition for Normality.