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tino4ka555 [31]
3 years ago
5

I know the answer just double checking Expand5(y+7)​

Mathematics
1 answer:
vekshin13 years ago
8 0
X=5(y+7) or x=5y+35
sorry if I’m wrong
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Find x.<br><br><br><br> 1.5<br> 2<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\
Vanyuwa [196]

Answer:

1.5

Step-by-step explanation:

3 0
3 years ago
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
3 years ago
A quantity p varies jointly with r and s. Which expression represents the constant of variation, k?
Zina [86]

The correct answer is p/rs.

In order to find this first state the direct variation with the constant k included.

p = krs

Now to find the value of k, we simply divide away the r and s

p/rs = k

3 0
2 years ago
Read 2 more answers
Please Help!! Brainliest Answer! Thank you
stiks02 [169]

Answer:

A

Step-by-step explanation:

O = 26.6

P is a right angle so:

P = 90

angles PQO = 180

To determine Q: triangle total - (P + O)

180 - (90 + 26.6)

180 - 116.6 = 63.4

Q = 63.4

To determine side lengths: a^2 + b^2 = c^2

4^2 + b^2 = c^2

*Variable c is always hypotenuse*

Need more information so find either b or c through SOH, CAH, TOA

SOH: sine = opposite/hypotenuse

CAH: cos = adjacent/hypotenuse

TOA: tan = opposite/adjacent

tan26.6/1 = b/4

Cross multiply

1 × b = 4 × tan26.6

b = 4tan26.6

b = 2.003050791

b is about 2

b = PQ

PQ = 2

Plug b value into pythagorean theorm

4^2 + 2^2 = c^2

16 + 4 = c^2

20 = c^2

square root of 20 = square root of c^2

4.47213.... = c

c is about 4.47

c = QO

5 0
3 years ago
Read 2 more answers
ILL MARK BRAINIEST IF YOU CAN DO THIS RIGHT!!!
Bumek [7]

Answer:  Slope: -1/2  

Step-by-step explanation:  To find slope take 2 points that lie on the line and use this formula to solve:  <em> </em>I will use (0, -2) and (2, -3) to solve

                                                                       ↑    ↑           ↑   ↑

y2 - y1                                                             x1  y1          x2  y2

-----------

x2 - x1

So, for this question, substitute the x and y values from the points above to solve.

-3 - (-2)      

----------- =  - 1/2

2 - 0

Hope this helped. :)

 

5 0
3 years ago
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