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baherus [9]
3 years ago
13

How many different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1

Mathematics
2 answers:
ElenaW [278]3 years ago
7 0

Answer:

8 X 10^(9)

Step-by-step explanation:

Originally we have 10 digit phone numbers excluding the area code.

For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)

But if we exclude 1 and 0 for the first digit, we are left with 8 digits.

8P1 X .......

In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.

8P1 X 10P1 X 10P1 X...

Adding the area code while assuming 10P1 is just 10...we get:

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

Very interesting question, thanks for the opportunity!

stealth61 [152]3 years ago
3 0

Answer:

8000000

Step-by-step explanation:

503-xxx-xxxx

for the last 7 digit: 2-9 .... 8 for first digit

                              0-9 .... 10 for digit 2 to digit 7

Total: 8*10*10*10*10*10*10 = 8000000

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You and your friends decide to camp for one night. Look at the diagram of your tent below. It is drawn on 1 cm squared paper. Th
Citrus2011 [14]

Answer:

1.Area of Porch =2.5m²

2.Number of people =3 people

Step-by-step explanation:

The porch area from the diagram has a dimension of 4 units by 10 units

One units =1cm

Thus the porch is drawn with dimensions of 4cm by 10 cm

Taking length is 10 cm and width as 4 cm, convert these dimensions according to the scale.

The scale is 1cm=0.25m

The width will be= 0.25×4=1 m

The length will be=0.25×10= 2.5m

Area of the porch is given by the formula;

length×width because its has a shape of a rectangle

Area of porch will be

=1m ×2.5m =2.5m²

2.

Find the dimensions of the tent

14 units by 10 units

Applying the scale on the dimensions by multiplying by 0.25

14×0.25=3.5m

10×0.25=2.5m

Width=2.5m

length=3.5m

Subtract the edge distance on both the length and width

Length will be=3.5-(0.25×2)=3.0m

Width will be=2.5-(0.25×2)=2.0m

Find the area remaining to be covered by the people while sleeping

=3.0×2.0=6m²

Area covered by sleeping bag and a ground mat

2m×1m=2m²

Number of people that can sleep in the tent

6m²÷2m²=3 people

8 0
3 years ago
Read 2 more answers
If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a
Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

c = \sqrt{64}

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

#SPJ4

3 0
1 year ago
If the cost of plastering 4 walls of a room at Rs 45 per sq. m is Rs 8100, find the area of the 4 walls of the room​
olga55 [171]

Step-by-step explanation:

Rs8,100 / (Rs45 per square meter)

= 180 square meters.

The area of the 4 walls of the room is 180 sq.m.

3 0
3 years ago
Use substitution to solve the system.<br><br> X= ?<br> Y= ?<br><br> 5x+4y = -10<br> x = 3y+17
nikklg [1K]

Answer:

x=3.4

y=-6.75

Step-by-step explanation:

5x+4y=-10  (equation 1 )

-5x+3y=-17  (equation 2)

7y=-27

y=-6.75

substitution (equation 1 ) y=-6.75

5x-27=-10

5x=17

x=3.4

4 0
3 years ago
Sin40°-sin20°/cos220°-cos200=√3​
Mumz [18]

Answer:

1.7320508

Step-by-step explanation:

7 0
3 years ago
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