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MArishka [77]
3 years ago
8

In a wildlife preserve, a random sample of the population of 150 raccoons was caught and weighed. The results, given in pounds,

were 16, 18, 18, 24, 25, 27, 28, 31, 31, and 32. Jean made the qualitative statement, "The average weight of the raccoon population is 26 pounds." Is her statement reasonable? Complete the explanation.
Jean's statement (select) reasonable because the median value of the data is pounds.
Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

The average is 24 so her answer is reasonable cause it is not too far off.

Step-by-step explanation:

Average = sum/count

(16 + 18 + 18 + 24 + 25 + 27 + 28 + 31 + 31 + 32)/10

240/10

24

24 is close to 26

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there are 3 method to show that 40 is the sum of two prime. among all the prime , find the difference between the two largest pr
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the difference is 39? for the answer

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Read 2 more answers
A one-stop flight from seattle to nyc can stop at boise, omaha, or chicago. the flight then connects to either la guardia or jfk
Sindrei [870]
The first and only stop of the flight can be Boise, Omaha or Chicago. This means there are 3 possibilities where to stop. From thee the flight connects to New York City, either to La Guardia or to JFK Airport.
1 possible route: Seattle-Boise-La Guardia
<span>2 possible route: Seattle-Omaha-La Guardia
</span><span>3 possible route: Seattle-Chicago-La Guardia
</span><span>4 possible route: Seattle-Boise-NYC
</span><span>5 possible route: Seattle-Omaha-NYC
</span><span>6 possible route: Seattle-Chicago-NYC
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Or in other words: There are two airports where the flight can arrive and for each of them there are three possible routes. So, in total there are 2*3=6 possible routes.
3 0
3 years ago
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
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