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3 years ago

Solve for b. -b - 19 = -3b – 9

Mathematics

1 answer:

8090 [49]3 years ago

3 0

Answer:

b=5

Step-by-step explanation:

-b - 19 = -3b – 9

Add 3b to each side

-b+3b - 19 = -3b+3b – 9

2b -19 = -9

Add 19 to each side

2b-19+19 = -9+19

2b = 10

Divide by 2

2b/2 =10/2

b=5

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7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

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Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

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b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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