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3 years ago

What’s the answer? Please help

Mathematics

1 answer:

blsea [12.9K]3 years ago

4 0

Answer:

Step-by-step explanation:

Since you are trying to find out half the number of students in a PE class, dividing would be most appropriate since you would be trying to find half.

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5 <k-2 <11 jjsjskkskrjrjjr

gavmur [86]

I hope this helps you

5 <k-2

5+2 <k

7 <k

k-2 <11

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7 <k <13

7 0

4 years ago

A cube-shaped box has a volume of 27 in.3 If the size of the box is increased, the volume, in cubic inches, of the box is modele

musickatia [10]

Answer

Are you taking the quiz for math 1? This bout to be real awkward if you aren't who I think you are :/

Step-by-step explanation:

4 0

3 years ago

A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that

Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

$P(A\cap B)=P(A).P(B)$

Now, According to question , we can get that

$P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}$

So,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}$

So, by using the conditional probability , which state that

$P(B\mid A)=\frac{P(A\cap B)}{P(A)}$

$P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}$

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

4 0

3 years ago

Please help me........

Gwar [14]

I beleve its 1.6 cm^2

4 0

3 years ago

Read 2 more answers

(please help!)<br> Add −1.25+2.5<br><br> Plot the first addend and the sum on the number.

AVprozaik [17]

Answer:

the answer of this question is 1.25

3 0

3 years ago

Read 2 more answers