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3 years ago

4 Questions:

Chemistry

1 answer:

marusya05 [52]3 years ago

8 0

Answer:

1) 3.0 moles.

2) 2.0 moles.

3) 2.0 moles of H atoms.

4) 4. 6.02 x 10²³.

Explanation:

Q1: How many moles of chlorine are present in 3 moles of MgCI₂?

MgCl₂ is dissociated according to the equation:

MgCl₂ → Mg + Cl₂.

Every 1.0 mole of Mg is dissociated to 1.0 mol of Mg and 1.0 mol of Cl₂.

∵ 1.0 mol of MgCl₂ gives 1.0 mol of Cl₂.

∴ 3.0 mol of MgCl₂ gives 3.0 mol of Cl₂.

Q2: How many moles of H₂0 are needed to produce 1 mole of O₂ in the following equation? 2H₂O → 2H₂ + O₂.

From the balnced equation:

2H₂O → 2H₂ + O₂.

2.0 moles of H₂O produce 2.0 moles of H₂ and 1.0 mole of O₂.

∴ We need 2.0 moles of H₂O to produce 1.0 mole of O₂.

Q3: How many moles of hydrogen atoms are present in 1 mole of H2 gas?

H₂ is dissociated according to:

H₂ → 2H.

1.0 mol of H₂ is dissociated to produce 2 atoms of H.

∴ 1.0 mol of H₂ contains 2.0 moles of H atoms.

Q4: How many atoms or molecules are in a mole?

It is known that every mole of any compound contains Avogadro's number of atoms or molecules (6.022 x 10²³).

So, the answer is: 4. 6.02 x 10²³.

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At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of

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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

Answer: The mass of carbon dioxide that can be dissolved is 1.7 grams

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{CO_2}=K_H\times p_{CO_2}$

where,

$K_H$ = Henry's constant = $0.031M/atm$

$C_{CO_2}$ = molar solubility of carbon dioxide gas

$p_{CO_2}$ = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

$C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = $0.0905mol/L$

Volume of solution = 425 mL

Putting values in above equation, we get:

$0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g$

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

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3 years ago

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Answer:

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3 years ago