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irina [24]
3 years ago
11

How many hours in a 100,000 minutes ?

Mathematics
2 answers:
kondor19780726 [428]3 years ago
6 0
The answers will be 1666.667
Irina18 [472]3 years ago
4 0
100000/60 = 1666.667 hours 
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Ava has a credit card that gets her a 5% discount on every purchase and free shipping when used online. The annual percentage ra
8_murik_8 [283]

Answer:

1:$10

2:$13.06

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a
s2008m [1.1K]

Answer:

3 boxes.

Step-by-step explanation:

Let x represent number of 1.2 pounds boxes.

We have been given that Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a small box.

The oranges covered in x small boxes would be 1.2x    

Oranges packed in 5 large boxes would be 5\times 2.4\text{ pounds}=12\text{ pounds}.

We can represent our given information in an equation as:

1.2x+12=15.6  

1.2x+12-12=15.6-12  

1.2x=3.6  

\frac{1.2x}{1.2}=\frac{3.6}{1.2}  

x=3  

Therefore, the minimum number of small boxes required to ship the rest of the oranges would be 3 boxes.

7 0
3 years ago
Who is correct? Explain your reasoning.
kap26 [50]
In order to get who was right we need to solve the expression:
2a^2b(-2ab^3)^-2
The above can be written as fraction to get:
(2a^2b)/(-2ab^3)^2
=(2a^2b)/(4a^2b^6)
=1/2(a^(2-2)b^(1-6))
=1/2a^0b^-5
=1/2b^(-5)
This implies that neither of the was right

3 0
4 years ago
Sam saw 2 bottles of ketchup at the store for the same price. One bottle contained 4 pints of ketchup and the other contained 1.
Ilia_Sergeevich [38]
I do believe that it's the bottle with the 4 pints of ketchup. 4 pints is 2 quarts 
3 0
3 years ago
V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

7 0
3 years ago
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