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Vedmedyk [2.9K]
3 years ago
15

The Crayola crayon company can make 2400 crayons in 4 minutes. How many crayons can they make in 15 minutes? Solve this problem

by setting up a proportion
Mathematics
1 answer:
algol [13]3 years ago
3 0

The Crayola crayon company can make 9000 crayons in 15 minutes.

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Arrange the following numbers from smallest to largest: 3.04, 3<br> 10<br> 3.024
andre [41]

Answer:

3, 3.024, 3.04, 10

I'm sorry if I misunderstood.

Good luck mate! :)

Please add Brainliest if you'd like, not that it matters.

Remember to try your best every day!

8 0
3 years ago
How many half metres together measure 4 1-2m
telo118 [61]
Make it an improper fraction with two as the denominator, and you'll get 9/2. There are 9 halves in 4 1/2 meters
5 0
3 years ago
How do you convert 17 cmon minute to miles an hour
eimsori [14]

Answer:

0.006 miles per hour

Step-by-step explanation:

We are given;

Speed in cm per minute ( 17 cm per min)

We are required to convert cm per minute to miles an hour

we need to know that;

1 miles = 160934 cm

1 hour = 60 minutes

We can convert 17 cm to miles and 1 minute to hours

17 cm = 17 ÷ 160934 cm

          = 17/160934

1 minute = 1/60 hour

Therefore;

In miles per hour;

  = (17/160934) ÷ (1/60)

  = 0.00634 miles per hour

  = 0.006 miles per hour

Therefore, 17 cm per minute is equivalent to 0.006 miles per hour

4 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
How would you solve cos(5x)=sin(10x) ?
Tomtit [17]
We will use double angle identities:
cos (5x ) = sin (10x )   
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
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4 0
3 years ago
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