Question

What were the dimensions of the original photo?

Answer 1

Answer:

A. 11 inches by 11 inches

Step-by-step explanation:

We have been given an equation $(x-3)^2=64$, where x represents the side measure of the  original photo. The equation represents the area the area of the reduced photo. We are asked to find the dimensions of the original photo.

Let us solve for x by taking positive square root of both sides.

$\sqrt{(x-3)^2}=\sqrt{64}$

$\sqrt{(x-3)^2}=\sqrt{8^2}$

$x-3=8$

Add 3 on both sides:

$x-3+3=8+3$

$x=11$

Therefore, the dimensions of the original photo are 11 inches by 11 inches and option A is the correct choice.

Answer 2

Answer is 11 by 11 Which is A

Step-by-step explanation:

I just guessed and got it right