Answer:
1. C points radially outward from origin
2. A. Points radially outward from z origin
3. D. Radially inwards toward origin
4. B. Inwards towards the z axis
Step-by-step explanation:
1.
X²+y²+z² = f(x,y,z)
Vector P<x,y,z>
2<x,y,z> = 2p
The answer is c points radially outward from origin
2.
X²+y² = f(x,y)
<2x,2y,0>
Points radially outward from z axis
3.
D. Points radially inwards toward origin
4.
B. Points radially inwards toward the z axis.
Please check attachment for solutions to answers 3 and 4
Answer:
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 590 hours.
This means that
Find the probability of a bulb lasting for at most 605 hours.
This is the pvalue of Z when X = 605. So
has a pvalue of 0.8413
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Answer:
That is correct..very good job!
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
You always start with the equasions in parenthesis. 3-1 is 2 and 8 divided by 2 is 4. Then you can move on to the next part of the eqasion. You start by subtracting 2 from 5 and then multiplying that by 2.then you add up the answers and you gat 8.