All categories

3 years ago

What is the ratio of 200 to 350

Mathematics

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

Simply Put:

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 200 and 350 is 50

Divide both terms by the GCF, 50:

200 ÷ 50 = 4

350 ÷ 50 = 7

The ratio 200 : 350 can be reduced to lowest terms by dividing both terms by the GCF = 50 :

200 : 350 = 4 : 7

Therefore:

200 : 350 = 4 : 7

Step-by-step explanation:

You might be interested in

A bus can hold up to 30 students. 10 have already got in class. the inequality is<br>

stiv31 [10]

Answer:

20? i dont know hopefully im right

Step-by-step explanation:

3 0

3 years ago

HELP ASAP PLSS BUT only answer if you know it's correct

kvasek [131]

= it is equal to because the absolute value of |-5| is 5

6 0

2 years ago

Read 2 more answers

Mike makes a commission of 10% on each TV set sold at store. Each TV costs $120. How much

GrogVix [38]

Answer:

$300

Step-by-step explanation:

10% = .1 and each TV costs 120 so .1*120=12 then you take 12*25 since 12 is the money he makes for seeling the tv multiplied by the total TV's sold and you get 300 so Mike makes $300

5 0

3 years ago

Find B on AC that is 2/5 of the distance of A to C.

salantis [7]

Answer:

Step-by-step explanation:

AC = 5, ao AB = 2.

This means B = -1+2 = 1.

3 0

1 year ago

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

3 years ago