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blsea [12.9K]
4 years ago
14

What is 65.85 rounded to the nearest tenth

Mathematics
2 answers:
patriot [66]4 years ago
8 0
65.85 rounded to the nearest tenth is 65.9 because the 5 in the hundredths place is large enough to round the 8 to a 9. 
Elena L [17]4 years ago
3 0
It's is 65.90 because 5 or more raise the score 4 or less let it rest
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Identify the solution set of the given inequality using the given replacement set.
scoundrel [369]
Another user previously answered this same question and had a good rating, his answer was as follows:

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A gazelle can change its speed from 0 to 45 mph in 2 seconds. What is the gazelle's acceleration?
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If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?
andre [41]

The value of the x will be 12. The value of the x is obtained from the condition,(f – g)(x) = 0

<h3>What exactly is a function?</h3>

A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.

Given function;

f(x) = 16x – 30

g(x) = 14x – 6

⇒(f – g)(x) = 0

⇒(16x – 30)-(14x – 6)=0

⇒16x-30-14x+6=0

⇒2x-24=0

⇒x=24/2

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Hence, the value of the x will be 12.

To learn more about the function, refer to:

brainly.com/question/5245372

#SPJ1

8 0
2 years ago
The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of
julia-pushkina [17]

Answer:

180.4~cm^2

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

A=2\pi rh

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

A=2\pi rh+2\pi r^2

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

A=2\pi (3.25)(8.5)

A=173.6~cm^2

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

A_o= 0.8*8.5=6.8~cm^2

The total area of the label is:

A=173.6~cm^2+6.8~cm^2=180.4~cm^2

The area of the label is \mathbf{180.4~cm^2}

5 0
3 years ago
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