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Alexandra [31]
2 years ago
5

What is the

le" class="latex-formula"> * 8 / 4?
Mathematics
1 answer:
morpeh [17]2 years ago
4 0
6.32455532 is what my calculator says.
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PLEASE HELP SOLVE!! WILL MARK THE BRAINIES
quester [9]

Answer:

ABC

Step-by-step explanation:

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2 years ago
Help please!! (attachment below)
Aleksandr-060686 [28]

It’s function one cause if you find the slope on the table it’s 3/1 which is basically just 3. Then the y-intercept is -3.

Function 1 slope is 5 or 5/1 and y-intercept is 4

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Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
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3 years ago
What is 7 divided by 1/3 in multiplication
sveta [45]
It would be 7x3 which would equal 21. Hope that helped!
4 0
3 years ago
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Please help me with a) and b) I’m very lost, please explain and how you got your answer
Karo-lina-s [1.5K]

To solve A, complete the square for both variables.

The center is (6,4)

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