Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
The population of bacteria growed rapidly in section B, but stayed the same rate in Section C
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Answer:
it okay
Explanation:
can you help me with this question According to Frost in his poem "The Road Not Taken," what kind of difference did taking one road over another road make? A. It made a good difference, B. It made a bad diference, c. Frost does not say
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