The answer is C. large changes in allele frequencies can occur in a short time.
Genetic drift is a change in the frequency of alleles in a population as a result of random sampling of organisms and it decreases genetic variation of the population. In specific circumstances, large and rapid changes in allele frequencies can occur in a short time. The smaller the population, the more susceptible it is to genetic drift.
Answer:
The scaling exponent will be 0.75
Explanation:
According to a famous article by Max Kleiber*, the scaling of the metabolic rate or energy consumption for mammals Pmetab (measured in kcal/day) with the body mass Mb (measured in kilograms) is P metab = 70 Mb^0.75 .
What is the scaling exponent (the quantity x in a scaling law A = cMbx) for the specific metabolic rate as a function of the animal’s body mass?
he scaling of the metabolic rate or energy consumption for mammals P=kcal/day
Mb=body mass in kilograms
Comparing
P metab = 70 Mb^0.75 .
with A = cMb^x
the scaling exponent will be 0.75
metabolic rate is the energy(in kilojoule) consumed at rest. it accounts for the highest amount of energy a body consumes daily
Answer:
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Explanation:
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Answer:
1. Liver
2. Liver and Kidneys
3. Mitochondria
4. Lumen of the small intestines
5. Liver
Explanation:
1. Glucose is phosphorylated into glucose-6-phosphate which is the first step of both glycogen synthesis and glycolysis, this process occurs in the liver
2. Glucose 6-phosphate is a product of a process named gluconeogenesis which occurs in the liver it serves as a substrate for glucose-6-phosphatase in the liver.
3. Creatinine kinase is an enzyme that catalyzes the phosphorylation of creatine. In regeneration process of ATP, creatine phosphate transfers a high-energy phosphate to ADP which produces ATP and creatine
4. Initially lipase digestion lipase digestion happens in the small intestine where the bile salts reduce the surface tension of the fat droplets allowing the lipases to attack the triglyceride molecules. These molecules are taken up into the epithelial cells that line the intestinal wall, where they are resynthesized into triglyceride
5. The job of the liver is to produce ketone bodies. If the liver had this enzyme, the ketone bodies it produces would be immediately broken down by the liver before they are released, thereofore, no release of ketone bodies into the bloodstream
Answer:
DNA has four nucleobases: adenine, thymine, guanine, and cytosine. The nucleobases in a DNA strand have preferred partners to form hydrogen bonds with. Cytosine pairs with guanine, and adenine pairs with thymine. These are the base pairing rules that allow DNA replication and protein synthesis to happen.
Explanation:
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