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KonstantinChe [14]
3 years ago
12

HELLLLLLPPPPPPPPPPPPPPP

Mathematics
1 answer:
Savatey [412]3 years ago
7 0
What do you need help with
You might be interested in
Write an expression to find the total cost of buying b paperback books and m magazines if magazines cost $4.95 each and paperbac
xxTIMURxx [149]

Answer:

Total\ cost=7.95b+4.95m

Step-by-step explanation:

Paperback Books:

Number of books=b

Cost of 1 book=\$7.95

Cost\ of\ all\ paperback\ books=cost\ of\ 1\ book\times number\ of\ books\\\\Cost\ of\ all\ paperback\ book=7.95\times b=7.95b

Magazines:

Number of magazines=m

Cost of 1 magazine=\$4.95

Cost\ of\ all\ magazine=cost\ of\ 1\ magazine\times number\ of\ magazine\\\\Cost\ of\ all\ magazines=4.95\times m=4.95m

Total\ Cost=Cost\ of\ paperback\ books+Cost\ of\ magazine\\Total\ Cost=7.95b+4.95m

8 0
3 years ago
Find the range from 54 to (-13)
Korolek [52]
If you were at 54 on the number line you would have to cross zero and go an extra 13 steps to get to -13.
So we want the difference between 54 and -13   or 54- -13 which becomes 54+13 which is 67 - that is the range
5 0
3 years ago
Greta has finished reading 15 pages from a 20-page magazine article. Which of these is another way to express the fraction of th
Verizon [17]
Answers: H

Work: 15/20=0.75
8 0
3 years ago
After losing 22 lb in each of the first two
Pavel [41]

Answer:

Weight on 1 may = 104 lb

Step-by-step explanation:

Given:

Weight on last may = 110 lb

Weight gain for to week = 2 x 19 = 38 lb

Weight lose for to week = 2 x 22 = 44 lb

Find:

Weight on 1 may

Computation:

Weight on 1 may = Weight on last may - Weight gain for to week + Weight lose for to week

Weight on 1 may = 110 - 44 + 38

Weight on 1 may = 104 lb

4 0
3 years ago
Please help me !! (no this isnt a test/exam)
stiv31 [10]

Answer:

  infinitely many

Step-by-step explanation:

Add 12-y to both sides of the second equation to put it into standard form like the first equation:

  y +(12 -y) = (x -12) +(12 -y)

  12 = x - y . . . simplify

  x - y = 12 . . . . second equation in standard form

We see this is identical to the first equation. That means every solution of the first equation is also a solution of the second equation. There are infinitely many solutions.

8 0
2 years ago
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