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3 years ago

1/5x + 4 =1/3x-8 Can you show your work too? That would be great

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

Step-by-step explanation:

1/5x+4=1/3x-8

add 8 to both sides and subtract 1/5x from both sides

4+8=1/3x-1/5x

12=5/15x-3/15x

12=2/15x

divide both sides by 2/15

12÷2/15=x

when dividing by a fraction, invert and multiply

12*15/2=x

90=x

CHECK:

1/5(90)+4=1/3(90)-8

18+4=30-8

22=22

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(x+1)(2x-4)(1/x+1) = (x+1)(2x-4)(1-5/2x-4)

Sunny_sXe [5.5K]

Solution:

$(x+1)(2x-4)(\frac{1}{x}+1)=(x+1)(2x-4)(1-\frac{5}{2x}-4)\\(x+1)(2x-4)(\frac{1}{x}+1)-(x+1)(2x-4)(1-\frac{5}{2x}-4) = 0\\(x+1)(2x-4)(\frac{1}{x}+1-(1-\frac{5}{2x}-4))=0\\(x+1)(2x-4)(\frac{1}{x}+1-(-3\frac{5}{2x}))=0\\(x+1)(2x-4)(\frac{1}{x}+1+3+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{1}{x}+4+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{5x^{2}+8x+2}{2x} )=0\\$

$x+1=0\\x=-1\\\\2x-4=0\\x=2\\\\\frac{5x^{2}+8x+2}{2x}=0\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}$

Answer:

$x=-1\\x=2\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}$

<em>Hope this was helpful.</em>

8 0

3 years ago

Heloo i really need help! any helo would he appreciated!

trapecia [35]

Answer:

The measure of angle DPA is 39°

Step-by-step explanation:

step 1

Find the value of x we know that arc AB+arc BC+arc CD+arc DA=360°

substitute the values

(5x+10)°+(x+1)°+3x°+(3x+25)°=360°

Solve for x

(12x+36)°=360°

12x=360°-36°

x=324°/12=27°

step 2 Find the measure of angle DPA

we know that The measurement of the external angle is the semi-difference of the arcs which comprises

m∠DPA=(1/2)[arc DA-arc BC]

arc DA=3(27)+25=106°

arc BC=27+1=28°

substitute the values

m∠DPA=(1/2)[106°-28°]=39°

6 0

3 years ago

Read 2 more answers

Which answer is the best estimate of the residual value when x = 1?

Rasek [7]

The correct answer is A -1.5

7 0

3 years ago

Read 2 more answers

Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te

motikmotik

Given:

There are given that the cos function:

$cos210^{\circ}=-\frac{\sqrt{3}}{2}$

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

$cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}$

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

$\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}$

Then,

Put the value of cos210 degrees into the above function:

So,

$\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}$

Final answer:

Hence, the value of the cos(105) is shown below: