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Gnom [1K]
3 years ago
11

Emily sold 66 boxes of cookies for a fundraiser. If she sold 40% of the total boxes of cookies sold for the fundraiser, how many

boxes of cookies were sold for the fundraiser total?
Mathematics
1 answer:
Kitty [74]3 years ago
5 0
She sold about 40 boxes because you do 66 - 40% = 39.6 or about 40
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What os the correct question and why​
mr_godi [17]

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8 0
2 years ago
The length of a rectangle is (2x+5) units and the breadth is (3x-1) units .Find the perimeter and the area of the rectangle.
jolli1 [7]

Answer:

Perimeter =  10x + 8 units.

Area = 6x^2 + 13x - 5 units^2.

Step-by-step explanation:

The perimeter  is 2*length + 2*breadth

= 2(2x + 5) + 2(3x - 1)

= 4x + 10 + 6x - 2

= 10x + 8 units.

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= (2x + 5)(3x - 1)

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= 6x^2 + 13x - 5 units^2.


7 0
2 years ago
Please Hurry ...Which expression is equivalent to
swat32

Answer:

\huge\boxed{\sf \frac{160rs^5}{t^6}}

Step-by-step explanation:

\sf 5r^6t^4 ( \frac{4r^3s^tt^4}{2r^4st^6} ) ^5

Using rule of exponents \sf a^m/a^n = a^{m-n}

\sf 5r^6t^4 ( 2 r^{3-4} s^{2-1}t^{4-6})^5\\5r^6t^4(2r^{-1}st^{-2})^5\\5r^6t^4 * 32 r^{-5}s^5t^{-10}

Using rule of exponents \sf a^m*a^n = a^{m+n}

\sf 160 r^{6-5}s^5t^{4-10}

\sf 160 rs^5 t^{-6}

To equalize the negative sign, we'll move t to the denominator

\sf \frac{160rs^5}{t^6}

8 0
2 years ago
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
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