Because there are 4 students who passed in all subjects, we can say that only 2 students passed in English and Mathematics only, only 3 students passed in Mathematics and Science only, and no one passed in English and Science only.
Given that we have deduced the number of students who passed in two subjects, we can now solve for the number of students who passed only one subject.
English = 15 - (4 + 2 + 0) = 9
Mathematics = 12 - (4 + 3 + 2) = 3
Science = 8 - (4 + 3 + 0) = 1
1. In English but not in Science,
9 + 2 = 11
2. In Mathematics and Science but not in English
3 + 3 + 1 = 7
3. In Mathematics only
= 3
3. More than one subject only
3 + 4 + 2 + 9 = 18
It will really be helpful if you draw yourself a Venn Diagram for this item.
Answer:
1 1/2
Step-by-step explanation:
<u>Answer:</u>
<u>Step-by-step explanation:</u>
<u>Let's find 'a' using Pythagoras theorem.</u>
- => 4² = 2² + a²
- => 16 = 4 + a²
- => 12 = a²
- => a = √12
- => a = √2 x 2 x 3
- => a = 2√3
- => a = 2 x √3
- => a = 2 x 1.732
- => a = 3.464 = 3.5 (Estimated)
Hoped this helped.
What? This isn’t a question
