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garri49 [273]
3 years ago
7

Solve using elimination. 6x + 8y = -4 -6x - 10y = 14

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
3 0

Answer:

x = 6, y = -5.

Step-by-step explanation:

6x + 8y = -4

-6x - 10y = 14    Adding will eliminate  the terms in x:

0 - 2y = 10

y = 10/-2 = -5,

Plug this into the second equation:

-6x - 10(-5) = 14

-6x = 14 - 50 = -36

x = -36/-6

x = 6.

bearhunter [10]3 years ago
3 0

Answer:

x = 6

y = -5

Step-by-step explanation:

Add the 2 together because the 6x and -6x cancel out

   6x + 8y = -4

+(-6x - 10y = 14)

        -2y = 10

        \frac{-2y}{-2} = \frac{10}{-2}

       y = -5

Then plug into y to get x.

 6x + 8(-5) = -4

  6x - 40 = -4

      + 40 + 40

  6x = 36

  \frac{6x}{6}  = \frac{36}{6}

 x = 6

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7 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
What is 5+2? Ive been totally stuck on this for the longest time. I really need help
eduard

that's a tricky one!

but it is 7 i believe

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3 years ago
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