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garri49 [273]
3 years ago
7

Solve using elimination. 6x + 8y = -4 -6x - 10y = 14

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
3 0

Answer:

x = 6, y = -5.

Step-by-step explanation:

6x + 8y = -4

-6x - 10y = 14    Adding will eliminate  the terms in x:

0 - 2y = 10

y = 10/-2 = -5,

Plug this into the second equation:

-6x - 10(-5) = 14

-6x = 14 - 50 = -36

x = -36/-6

x = 6.

bearhunter [10]3 years ago
3 0

Answer:

x = 6

y = -5

Step-by-step explanation:

Add the 2 together because the 6x and -6x cancel out

   6x + 8y = -4

+(-6x - 10y = 14)

        -2y = 10

        \frac{-2y}{-2} = \frac{10}{-2}

       y = -5

Then plug into y to get x.

 6x + 8(-5) = -4

  6x - 40 = -4

      + 40 + 40

  6x = 36

  \frac{6x}{6}  = \frac{36}{6}

 x = 6

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A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

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Change from $20 after spending $13.76
tamaranim1 [39]
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2 years ago
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Answer:

Step-by-step explanation:

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2 years ago
(−7c+8d)0.6 distributive property
Ksivusya [100]

We are given

(-7c+8d)0.6

we can use distribute property

Distributive property:

(A+B)C=A*C+B*C

so, we can write it as

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3 years ago
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dybincka [34]

Answer: 1/5

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