All categories

3 years ago

For the function , if P = 8 and r = 0.08, then what is the value of f(8) to the nearest tenth?

Mathematics

1 answer:

meriva3 years ago

6 0

I think its A. I'm not really sure

You might be interested in

I'm making a table.

Ivenika [448]

Well I think I can help you out ...
if you assume input x=2
the output will be as following :
y= -1/3(2)+2
=-2/3+2
=-2/3+6/3
=(-2+6)/3
=4/3
=1.333

3 0

4 years ago

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

avanturin [10]

Please see attached. I hope this helps!
Thanks!!

8 0

4 years ago

I earned $100. I wish to give 15% of this to my mother. How much should I give her?

garik1379 [7]

<h2><em>All of it. Be kind to your mother.</em></h2><h2><em></em></h2><h2><em></em></h2><h2><em></em></h2><h2><em>In all seriousness, 15% of 100 is itself. 15. If it was 27%, it'd be 27. So on and so forth.</em></h2>

6 0

3 years ago

Read 2 more answers

The sum of two consecutive odd integers is 156. Which is an equation that can be used to solve for x?

satela [25.4K]

Answer:

Below.

Step-by-step explanation:

We can write an odd integer as 2x + 1 so consecutive odd digits would be 2x + 1 and 2x + 3, so the equation is:

2x + 1 + 2x + 3 = 156

4x + 4 = 156 can be used to solve for x and find the integers.

4x = 152

Dividing through by 4:

x = 152/4 = 38

So the 2 integers are 2(38) + 1 and 2(38) + 3

= 77 and 79.

7 0

4 years ago

Question 1(Multiple Choice Worth 1 points)

weqwewe [10]

Answer:

f(x)=-1/2x+3

Step-by-step explanation:

In this problem, the student is running a 3-kilometer race.

This means that the total length of the race is 3 km.

We also know that the student runs 1 kilometer every 2 minutes. For a uniform motion, the speed is given by

$v=\frac{d}{t}$

where in this case,

d = 1 km is the distance

t = 2 min is the time

So the speed is

$v=\frac{1}{2}$

We can therefore write the distance covered by the student (from the starting line) after x minutes as

$y'=\frac{1}{2}x$

However, here we want to write an expression for the distance of the student from the finish line.

Since the distance from the finish line at x = 0 is 3, therefore the distance from the finish line after x minutes is:

d = 3 - y'

$y=3-\frac{1}{2}x$

which corresponds to the option:

f(x)=-1/2x+3

3 0

4 years ago