Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
x=280
Step-by-step explanation:
We have, 15% × x = 42
or,
15
100
× x = 42
Multiplying both sides by 100 and dividing both sides by 15,
we have x = 42 ×
100
15
x = 280
If you are using a calculator, simply enter 42×100÷15, which will give you the answer.
Answer:
50%
Step-by-step explanation:
So there are 90 2 digit numbers. There are 45 2 digit odd numbers.
The probability should be 50%
Y + 4 + 3(y+2) first distribute the 3
y + 4 + 3y + 6 then add like terms
4y + 10
therefore your answer should be 4y + 10
