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Naya [18.7K]
3 years ago
5

How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antif

reeze?
Mathematics
1 answer:
Alchen [17]3 years ago
8 0
Let x be the number of gallons.

(x)(80%) + (60)(30%) = (x+60)((70%)

0.8x + 18 = 0.7x +42

0.8x - 0.7x = 42-18

0.1x = 24

and x = 240 Gal.

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\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}
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