The triangular prism has 5 faces; two triangle faces and three rectangular faces.
We can find the area of one of the triangle faces by doing ((base * height) / 2). In this case, it would be ((2 * 2) / 2), which of course would equal 2"². Multiplied by two for the two triangles, which would be 4.
To find the area of one of the rectangles, we do (length * base), which would be (5 * 2) in our case, giving us 10. Multiply by 3 for the 3 faces, and we got 30"².
30 + 4 = 34"²
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
10, or 17.32050
Step-by-step explanation:
132 x 14.1% = 18.612
So 18.612 rounded to 18.6
Answer:
x y
−
6 1
−
5 7
/4
−
4 2
−
3 7
/4
−
2 1
Step-by-step explanation: