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Ira Lisetskai [31]
3 years ago
6

you are playing a card game with friends.at one point,you double your score.in the next hand you lose 75 points.you end up with

-25 points. how many points did u have before doubling your score
Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Let x be your initial score.

You double it, so your score becomes 2x.

You lose 75 points, so your score becomes 2x-75

This equals -25, so we have the following equation:

2x-75=-25 \iff 2x=50 \iff x=25

In fact, things went like this:

You start with 25 points

You double your score, and you have 50 points

You lose 75 points and end with -25 points.

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Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

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