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Sergio039 [100]
4 years ago
5

The dot plot below shows the number of wings contestants in a wing-eating contest ate.

Mathematics
2 answers:
Stolb23 [73]4 years ago
6 0

A.18 is the absolute deviation

Natali [406]4 years ago
4 0

Answer:

the answer is D. 1.52

Step-by-step explanation:

you want to add all the numbers then divide by 10

<u>15 + 15 + 17 + 18 + 18 + 18 + 19 + 20 + 20 + 21</u>

                             10

then you find the difference between the mean and data point

Data point = <u>15    15    17    18     18     18     19    20    20     21</u>

Mean Diff  = 3.1   3.1     1.1    0.1   0.1   0.1    .9      1.9    1.9    2.9

then add the differences

<u>3.1 + 3.1 + 1.1  + 0.1 + 0.1  +  0.1 + .9 + 1.9 + 1.9  + 2.9</u> and divide by 10

                                    10

<em>absolute deviation is 1.52 wings.</em>

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Answer:

Hypotenuse = 14.1421 inches (rounded off to four decimal values)

Step-by-step explanation:

The legs of an isosceles triangle both measure 10 inches

Since the triangle is a right triangle,

We apply the Pythagorean Theorem to find the height of the hypotenuse

a² + b² = c²

a = 10 inches, b = 10 inches and (c) is the hypotenuse whose value we don't know.

So; 10² + 10² = c²

c² = 100 + 100

c² = 200

c = \sqrt{200} = 14.1421356237 inches

The hypotenuse is 14.1421 inches (answer rounded off to four decimal values)

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3 years ago
The first steps in writing f(x) = 3x^2 -24x+10 in vertex form what is the function written in vertex form
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3 years ago
Two planes start flying towards each other simultaneously from two different cities. The distance between the cities is 960 mile
ANTONII [103]

Answer:

257.5 mph

332.5 mph

Step-by-step explanation:

The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is

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Calling v1 and v2 the velocities of the two planes, we have the following equations:

(1) v_1 = v_2 + 75 --> velocity of plane 1 exceeds velocity of plane 2 by 75 mph

(2) v_1 t+ v_2 t=885 --> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)

Substituting t=1.5 h, the second equation becomes:

1.5 v_1+1.5 v_2=885\\v_1 + v_2 = 590

By substituting (1) into this last equation, we find:

(v_2+75)+v_2 = 590\\2v_2 + 75 = 590\\2v_2 = 515\\v_2=257.5

And substituting this back into eq.(1), we find

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So, the speeds of the two planes are

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3 years ago
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