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insens350 [35]
3 years ago
5

The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas

s?
Chemistry
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm

Density is equal to mass per unit volume.

d=\dfrac{m}{V}

m is mass of the cylinder

V is the volume of the cylinder

V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3

So,

m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g

So, the mass of the cylinder is 1.51 grams.

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How many grams of nh3 can be produced from 3.72 mol of n2 and excess h2.
olganol [36]
N₂       + 3H₂ ⇒ 2NH₃
1mol       :         2mol
3,72mol  :         7,44mol

n = 7,44mol
M = 17g/mol

m = n * M = 7,44mol * 17g/mol = 126,48g
7 0
3 years ago
What volume of 0.100 M HCl will react completely with 50.00 mL of 0.200 M NaOH?
skelet666 [1.2K]
Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
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from the formula
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7 0
3 years ago
013 10.0 points
34kurt

Answer:

this isn't immediately clear, it can be seen in ... CO2? 1. 6.0 × 10−23 g. 2. 44 g. 3. 7.31 × 10−23 g correct. 4. 6.0 × 10. 23 g. 5. 7.31 × 10 ... 40.0 grams of S will react leaving 10.0 grams. S unreacted. 013. 10.0 points ... FeCl2 and K2CO3 is ... 9. 1. There is no reaction. 2. KCl electrolyte. 3. CO2 gas. 4. FeCO3 precipitate. correct.

Explanation:

5 0
3 years ago
1) For the following reaction, 8.44 grams of carbon (graphite) are allowed to react with 9.63 grams of oxygen gas.C(graphite)(s)
Yuki888 [10]

Answer:

The answers to the question are

(a) 13.24 g

(b) (O₂)

(c) 4.8252 g

(2) 0.662 M/L

Explanation:

(a) To solve the question we write the equation as follows

C + O₂ → CO₂

That is one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide

number of moles of graphite = 8.44/12 = 0.703 moles

number of moles of oxygen = 9.63/32 = 0.3009

However since one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide, therefore, 0.3009 moles of oxygen will react with 0.3009 moles of  carbon to fore 0.3009 moles of  CO₂

The maximum mass of carbon dioxide that  can be formed = mass = moles × molar mass

= 0.3009×44 = 13.24 g

(b) The formula for  the limiting reagent (O₂)

Finding the limting reagent is by checking the mole balance of the reactants available to the moles specified in th stoichiometry of the reaction and selecting the reagent with the list number of moles

(c) The mass of excess reagent = 0.703 moles - 0.3009 moles = 0.4021 moles

mass of excess reagent = 0.4021 × 12 = 4.8252 g

(2) The molarity is given by number of moles per liter of solution, therefore

molar mass of mgnesium iodide = 278.1139 g/mol, number of moles of magnesium iodide in 23 g = 23g/ 278.1139 g/mol= 8.3 × 10⁻² M

Therefore the moles in 125 mL = (8.3 × 10⁻² M)/(125 mL) = (8.3 × 10⁻² M)/(0.125 L) = 0.662 M/L

3 0
3 years ago
What percent of earths total volume is the crust
vlada-n [284]

1%

Explanation:

The crust is the thinnest layer of the earth accounting for only 1% total volume of the planets.

Compositionally, the earth is divided into three layers which are the crust, mantle and the core.

  • The crust is the outermost layer of the earth. It rich in silicate minerals. The rocks are classified into igneous, sedimentary and metamorphic rocks.
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Learn more:

Mantle brainly.com/question/7623608

#learnwithBrainly

7 0
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