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insens350 [35]
3 years ago
5

The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas

s?
Chemistry
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm

Density is equal to mass per unit volume.

d=\dfrac{m}{V}

m is mass of the cylinder

V is the volume of the cylinder

V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3

So,

m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g

So, the mass of the cylinder is 1.51 grams.

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<h3>Further explanation</h3>

Given

62.41% C, 5.24% H, and 32.36% N

Required

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mol ratio

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H : 5.24/1.00784 = 5.1992

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Divide by 2.310(smallest)

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H : 5.1992/2.31 = 2.25

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The empirical formula : C₉H₉N₄

(C₉H₉N₄)n=346.40 g/mol

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