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Tpy6a [65]
3 years ago
8

The strongest elemental oxidizing agents are found in the _________ _________ region of the periodic table while the strongest r

educing agents are found in the ________ ________ region of the periodic table.
Chemistry
2 answers:
seraphim [82]3 years ago
5 0

Answer:

The strongest elemental oxidizing agents are found in the Group 17 region of the periodic table while the strongest reducing agents are found in the Group 1 region of the periodic table.

Explanation:

Strongest oxidizing agent means the elements which can oxidize others and themselves gets reduced easily. It means they can accept electrons easily. An element can gain electron easily if it may attain a half or full filled stability.

thus elements of group 17 is the region where we can found strongest elemental oxidizing agents.

Strongest reducing agents means the element can reduce others easily and thus can lose electrons easily. This is possible if an element attains a stability by losing electrons.  Thus elements of group 1 is the region where we can found reducing elemental reducing agent.

Slav-nsk [51]3 years ago
3 0

Strongest reducing agents are in Group 1 . For example lithium. The strongest oxidising agents are in Group 7 , For example Fluorine.

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5 0
3 years ago
A 10,0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is
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Considering the Charles' law, the gas would have a temperature of -109.2 C.

<h3>Charles' law</h3>

Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Charles' law is expressed mathematically as:

\frac{V}{T} =k

If you want to study two different states, an initial state 1 and a final state 2, the following is true:

\frac{V1}{T1} =\frac{V2}{T2}

<h3>Temperature of the gas in this case</h3>

In this case, you know:

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  • P2= 1800 psi
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You can see that the pressure remains constant, so you can apply Charles's law.

Replacing in the Charles's law:

\frac{10 L}{293 K} =\frac{6 L}{T2}

Solving:

\frac{10 L}{293 K} T2=6 L

T2=\frac{6 L}{\frac{10 L}{293 K} }

<u><em>T2=163.8 K= -109.2 C</em></u>

The gas would have a temperature of -109.2 C.

Learn more about Charles's law:

brainly.com/question/4147359?referrer=searchResults

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2 years ago
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3 years ago
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