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Tpy6a [65]
3 years ago
8

The strongest elemental oxidizing agents are found in the _________ _________ region of the periodic table while the strongest r

educing agents are found in the ________ ________ region of the periodic table.
Chemistry
2 answers:
seraphim [82]3 years ago
5 0

Answer:

The strongest elemental oxidizing agents are found in the Group 17 region of the periodic table while the strongest reducing agents are found in the Group 1 region of the periodic table.

Explanation:

Strongest oxidizing agent means the elements which can oxidize others and themselves gets reduced easily. It means they can accept electrons easily. An element can gain electron easily if it may attain a half or full filled stability.

thus elements of group 17 is the region where we can found strongest elemental oxidizing agents.

Strongest reducing agents means the element can reduce others easily and thus can lose electrons easily. This is possible if an element attains a stability by losing electrons.  Thus elements of group 1 is the region where we can found reducing elemental reducing agent.

Slav-nsk [51]3 years ago
3 0

Strongest reducing agents are in Group 1 . For example lithium. The strongest oxidising agents are in Group 7 , For example Fluorine.

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Answer:

Look at the picture.

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What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
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Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

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3 years ago
Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts
SOVA2 [1]

Answer:

\boxed{\text{Mg is the limiting reactant}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble the data in one place.

           2Mg + O₂ ⟶ 2MgO

n/mol:    2       5

Calculate the moles of MgO we can obtain from each reactant.

From Mg:  

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\text{Moles of MgO} = \text{2 mol Mg} \times \dfrac{\text{2 mol MgO}}{\text{2 mol Mg}} = \text{2 mol MgO}

From O₂:  

The molar ratio of MgO:O₂ is 2:1.

\text{Moles of MgO} = \text{5 mol O}_{2} \times \dfrac{\text{2 mol MgO}}{\text{1 mol O}_{2}} = \text{10 mol MgO}\\\\\boxed{\textbf{Mg is the limiting reactant}} \text{ because it gives the smaller amount of MgO}

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True it is odorless and it has no color
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3 years ago
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rewona [7]

Answer:

A

Explanation:

Ionic compounds are solids when at room temperature

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