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IceJOKER [234]
3 years ago
8

Please answer I'm begging!!!

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Keisha ran 2.4 miles more than Jamal.

Keisha ran 8.5 miles, how many miles did Jamal run?


m = the number of miles Jamal ran


2.4 + m = 8.5

[Keisha ran 2.4 more miles than Jamal(m), she ran a total of 8.5 miles]


2.4 + m = 8.5   Subtract 2.4 on both sides

m = 6.1


Jamal ran 6.1 miles (Your answer is the 2nd option)

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Find the distance of PQ<br> P(0,4) and Q(10,-6)
solong [7]

Answer:

PQ ≈ 14.14 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = P (0, 4 ) and (x₂, y₂ ) = Q (10, - 6 )

PQ = \sqrt{(10-0)^2+(-6-4)^2}

     = \sqrt{10^2+(-10)^2}

     = \sqrt{100+100}

     = \sqrt{200}

     ≈ 14.14 units ( to 2 dec. places )

4 0
2 years ago
Read 2 more answers
A sample of 900900 computer chips revealed that 49%49% of the chips do not fail in the first 10001000 hours of their use. The co
dedylja [7]

Answer:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

Step-by-step explanation:

The claim made by the company is that 52% of the chips do not fail in the first 1000 hours of their use.

A quality control manager wants to test the claim.

A one-proportion <em>z</em>-test can be used to determine whether the proportion of chips do not fail in the first 1000 hours of their use is 52% or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of chips do not fail in the first 1000 hours of their use is 52%, i.e. <em>p</em> = 0.52.

<em>Hₐ</em>: The proportion of chips do not fail in the first 1000 hours of their use is different from 52%, i.e. <em>p</em> ≠ 0.52.

The information provided is:

\hat p=0.49\\n=900\\\alpha =0.02

The test statistic value is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.49-0.52}{\sqrt{\frac{0.52(1-0.52)}{900}}}=-1.80

The test statistic value is -1.80.

Decision rule:

If the <em>p-</em>value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.07186 > <em>α</em> = 0.02.

The null hypothesis was failed to be rejected at 2% level of significance.

<u>Conclusion</u>:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

8 0
3 years ago
This writing prompts is hard
Solnce55 [7]
A.) Simplifying the equation would lead you to 15x^2-3x+9

b.) You know your answer is correct because you're adding the two polynomials together. 9x^2+6x^2 is 1tx^2. Now you have 2x-5x and since the negative is bigger, you get -3x. Then 5+4 is 9. You have no like terms therefore your answer is 15x^2-3x+9
7 0
4 years ago
Copy the table and fill in the missing values.
Maslowich

Answer:

t53

Step-by-step explanation:

5 0
3 years ago
I don’t know the answer and I can’t figure out how to do it
olga55 [171]

Answer:

I don't see an error at all. Is there an option for no error?

4 0
3 years ago
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