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Oksi-84 [34.3K]
3 years ago
6

Please help and ill give brainliest

Mathematics
2 answers:
slava [35]3 years ago
7 0
3.2 goes in the first and second blank, 8.7 is the final answer
daser333 [38]3 years ago
6 0

Answer:

w=8.7

Step-by-step explanation:

.......ask if more help needed

thanx

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It’s #11 that I need help with
wel

#11

Perimeter:

P = 2(W + L)

P = 2(3.5 + 6.5)

P = 2(10)

P = 20 units


Area:

A = WL

A = 3.5 * 6.5

A = 22.75 square units


5 0
4 years ago
A motorboat goes downstream in river and covers a distance between to coastal towns in 5 hours . It covers this distance upstrea
Radda [10]

Answer:

The speed of the boat in still water is 33 km/h

Step-by-step explanation:

Let us denote the speed of the boat in still water as x km/h.

Thus;

Since the speed of the stream is 3 km/h, then while going downstream, the total speed on the boat would be; (x + 3) km/h

Formula for distance = speed x time

Since we are told that the time taken to cover the distance downstream is 5 hours, then;

Distance covered in 5 hours = 5(x + 3) km

Therefore, distance between A and B is 5(x + 3) km

However, while going upstream the boat will work against the water current.

Therefore, its speed upstream will be (x − 3) km/h.

we are told that the time taken to cover the distance downstream is 6 hours, then;

Distance covered in 6 hours = 6(x − 3) km

Therefore, distance between A and B is 6(x - 3) km

The true distance between A and B has to be the same.

So,

5(x + 3) = 6(x - 3)

This gives;

5x + 15 = 6x - 18

15 + 18 = 6x - 5x

x = 33

Therefore, the speed of the boat in still water is 33 km/h

3 0
3 years ago
Name:<br><br> 1. Graph <br> a) y = 3x
oksian1 [2.3K]
This is how it looks on a graph.

3 0
3 years ago
What is the solution of the matrix equation?
Alenkasestr [34]

Answer:

<h3>(-12, 2)</h3>

Step-by-step explanation:

\left[\begin{array}{ccc}1&1\\2&3\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}8\\36\end{array}\right] \\\\\left[\begin{array}{ccc}x+y\\2x+3y\end{array}\right] =\left[\begin{array}{ccc}8\\36\end{array}\right]\\.\qquad\qquad\Downarrow\\\left\{\begin{array}{ccc}x+y=8&|\text{multiply both sides by (-2)}\\2x+3y=36\end{array}\right

\underline{+\left\{\begin{array}{ccc}-2x-2y=-16\\2x+3y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad y=20\\\\\text{Put the value of y to the firast equation:}\\\\x+20=8\qquad\text{subtract 20 from both sides}\\x=-12\\\\\boxed{(-12,\ 20)}

8 0
3 years ago
How is the Distributive Property used to simplify operations with scientific notation
Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

4 0
4 years ago
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