Let ΔABC be an obtuse triangle with sides a, b, c, that lie
opposite the angles A, B, C; with radius r of inscribed circle and
radius R of circumscribed circle; p semiperimeter. For obtuse triangle you can use all known area formulas:
1.
; (the area is equal to half of product of two sides and sine of angle that lies between these sides);
2.
;
3.
(Heron's formula);
4.
;
5.
.
So to find the decimal of the fraction you to divide 7/11
which equals C. 0.636363636363 the 63 goes on forever.
Length = 13 = (x + 3)
Width = 14 = (x + 4)
x2 + 7x + 12 = area of the rectangle
can be factored into
(x + 3)(x + 4)
Let L = one of the factors (x + 3)
Let W = the other factor (x + 4)
If x = 10 then
(10 + 3) = 13 = L
(10 + 4) = 14 = W
Checking this can be checked a couple of ways
Plug x = 10 into the original equation
x2 + 7x + 12
102 + 7(10) 12 = 100 + 70 + 12 = 182 = Area
Multiplty the factors
L x W = 13 x 14 = 182 = Area
I hope you find this useful if you have any questions please send me a message.
Ok.... so the first part is asking you what the perimeter of the picture itself is.
The picture is 5in by 7in.... SO you add 5+5+7+7=24.... So the perimeter of the pic is 24 inches.
Now part b
So the frame is one inch thick
This mean that the sides are now 2 inches longeron each side
SO we have 7+7+9+9=32
So the perimeter is 32
I hope that helped!!!!! If you dont understand something ask and i will reexplain ;)
