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3 years ago

Hello!!!! :) please help with this math problem! thank u so much!!!! i really appreciate it <3

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

3 0

Answer:

AGREE!

Step-by-step explanation:

"I agree with Lin, she used the correct formula to get this answer"

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Help me out pleaseeee

gladu [14]

4x - y = 5 --> 4x = y + 5

substitute

4x + 4y = -4

(y + 5) + 4y = -4

5y + 5 = -4

5y = -9

y = -1.8

solve x

4x = y + 5 = -1.8 + 5 = 3.2

x = 3.2/4 = 0.8

6 0

3 years ago

Find the range, mean, and standard deviation of the data set (3, 6, 9, 11, 15, 16) The range is 13 (Type a whole number.) The me

iris [78.8K]

Answer: The range is 13. The mean is 10. The standard deviation is 4.62 .

Step-by-step explanation:

The given data : 3, 6, 9, 11, 15, 16

Total number of data values : n = 6

The mean of data is given by :-

$\overline{x}=\dfrac{\sum^6_{i=1}x_i}{n}\\\\\Rightarrow\overline{x}=\dfrac{60}{6}=10$

The standard deviation is given by :-

$\sqrt{\dfrac{1}{n}(\sum^6_{i=1}(x_i-\overline{x})^2)}\\\\=\sqrt{\dfrac{1}{6}(\sum^6_{i=1}(x_i-10)^2)}\\\\=\sqrt{\dfrac{1}{6}\times(49+16+1+1+25+36)}=4.61880215352\approx4.62$

The range of the data : Maximum value -Minimum value

$=16-3=13$

6 0

3 years ago

HI umm CAN YOU PLEASE ANSWER ASAP!!!!

Marianna [84]

Answer:

Step-by-step explanation:

-6 divided by a positive number would make it a positive number welcome

8 0

3 years ago

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by

$F_{t+1}=F_t+\alpha (D_t-F_t)$

where

$F_{t+1}=Future Forecast$

$F_t=Present\ Period\ Forecast$

$D_t=Present\ Period\ Demand$

$\alpha =smoothing\ constant$

$F_{t+1}=5+0.2(7-5)$

$F_{t+1}=5.4$

Forecast for Period 3

$F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})$

$F_{t+2}=5.4+0.2\cdot (9-5.4)$

$F_{t+2}=6.12$

8 0

4 years ago

What is the effect on the graph of f(x)=1xf(x) = \frac{1}{x}f(x)=x

Doss [256]

Answer:

Step-by-step explanation:

8 0

3 years ago