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Ganezh [65]
3 years ago
14

I need help with number 12

Mathematics
1 answer:
fomenos3 years ago
7 0
Ok so when the divisor get larger, the quotient gets smaller. 
For example, 15 ÷ 3 = 5. If we make the divisor larger, you can see the quotient get smaller. 15 ÷ 5 = 3.
The same thing goes for the other way around. If the divisor gets smaller, the quotient gets larger. Hope I helped!
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8217 I think but I'm not sure
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Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

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Answer:

J=-50

Step-by-step explanation:

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A figure has four sides with two sets of parallel sides without more information which figure can be we be sure it could be
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Step-by-step explanation:

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A car travels the first 50km of its journey at an average speed of 25m/s snd the next 120km at an average speed of 80km/h. The c
Alex17521 [72]

Answer:

84,6km/h

Step-by-step explanation:

the whole journey was

in the first part the car travels 50km, in the second part 120km and in the third part we can find it with a simple rule of three

90km--->60 min

X<--------35min= 52.5 km the car made in the last part

50km+120km+52,5km=222.5km was all the journey

and he made it in:

  • the last part in 35min,
  • in the second part we know that the car was going at 80km/h and that he made 120km so:

80km--->60 min

120km--->90 min

  • in the first part we know that the car was going at 25m/s and he made 50km. 25m/s*1km/1000m*3600s/1h= we obtain the speed in km/h=90km/h

90km---->60min

50km---->x=33,333 min

The whole journey last 33,333min+90min+35min=158.333min

if we express that in hour = 158.333min*1hr/60min=2.63

the car made 222.5km in 2.63 hour

so the average speed was

222.5---->2.63hr

X--------1hr=84,6

the average speed was 84,6km/h

5 0
3 years ago
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