8217 I think but I'm not sure
Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
Answer:
J=-50
Step-by-step explanation:
Answer:
84,6km/h
Step-by-step explanation:
the whole journey was
in the first part the car travels 50km, in the second part 120km and in the third part we can find it with a simple rule of three
90km--->60 min
X<--------35min= 52.5 km the car made in the last part
50km+120km+52,5km=222.5km was all the journey
and he made it in:
- the last part in 35min,
- in the second part we know that the car was going at 80km/h and that he made 120km so:
80km--->60 min
120km--->90 min
- in the first part we know that the car was going at 25m/s and he made 50km. 25m/s*1km/1000m*3600s/1h= we obtain the speed in km/h=90km/h
90km---->60min
50km---->x=33,333 min
The whole journey last 33,333min+90min+35min=158.333min
if we express that in hour = 158.333min*1hr/60min=2.63
the car made 222.5km in 2.63 hour
so the average speed was
222.5---->2.63hr
X--------1hr=84,6
the average speed was 84,6km/h