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Alisiya [41]
3 years ago
13

Find the inverse

(x)=x^{2} +10" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

9514 1404 393

Answer:

  f^{-1}(x)=\pm\sqrt{x-10}

Step-by-step explanation:

You can find the inverse of

  y = f(x)

by solving for y:

  x = f(y)

__

  x = y² +10

  x -10 = y² . . . . . . . . subtract 10

  ±√(x -10) = y . . . . . take the square root

The inverse relation is ...

  \boxed{f^{-1}(x)=\pm\sqrt{x-10}}

__

It is not a <em>function</em> unless some restriction is placed on the domain of f(x).

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Answer:

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Step-by-step explanation:?

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