Question

Find the inverse(x)=x^{2} +10" align="absmiddle" class="latex-formula">

Answer 1

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Answer:

  $f^{-1}(x)=\pm\sqrt{x-10}$

Step-by-step explanation:

You can find the inverse of

  y = f(x)

by solving for y:

  x = f(y)

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  x = y² +10

  x -10 = y² . . . . . . . . subtract 10

  ±√(x -10) = y . . . . . take the square root

The inverse relation is ...

  $\boxed{f^{-1}(x)=\pm\sqrt{x-10}}$

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It is not a function unless some restriction is placed on the domain of f(x).