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3 years ago

5.) What is the force between a 3C charge and a 2C charge separated by a distance of 5 meters? *

Physics

1 answer:

lord [1]3 years ago

6 0

Answer:

21.6 x 10^8 N

Explanation:

F = k q1 q2 /r^2

= 9 x 10^9 x 3 x 2 / 5^2

= 21.6 x 10^8 N

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PLEASE HELP The image characteristics are...

VLD [36.1K]

According to the question, the object is placed at 2F

The ray diagram is shown in the figure attached.

According to the figure:

Object AB is at 2F₁

First, we draw a ray parallel to principal axis.

So, it passes through focus after refraction.

We draw another ray which passes through optical center.

So, the ray will go through without any deviation.

Where both refracted rays meet is point A' and the image formed is A'B'

This image is formed at 2F₂

We can say that:

Image is real.
Image is inverted.
Image is exactly the same size as the object.

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3 years ago

A ball is hit 1 meter above the ground with an initial speed of 40 m/s. If the ball is hit at an angle of 30 above the horizonta

Vika [28.1K]

Answer:

$t_t=4.131\ s$

Explanation:

Given:

height above the horizontal form where the ball is hit, $y=1\ m$

angle of projectile above the horizontal, $\theta=30^{\circ}$

initial speed of the projectile, $u=40\ m.s^{-1}$

Firstly we find the vertical component of the initial velocity:

$u_y=u.\sin\theta$

$u_y=40\times \sin30^{\circ}$

$u_y=20\ m.s^{-1}$

During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.

So final vertical velocity during the course of ascend:

$v_y=0\ m.s^{-1}$

Using eq. of motion:

$v_y^2=u_y^2-2g.h$ (-ve sign means that the direction of velocity is opposite to the direction of acceleration)

$0^2=20^2-2\times 9.8\times h$

$h=20.4082\ m$ (from the height where it is thrown)

Now we find the time taken to ascend to this height:

$v_y=u_y-g.t$

$0=20-9.8t$

$t=2.041\ s$

Time taken to descent the total height:

we've total height, $h'=h+y$ $=20.4082+1$

$h'=u_y'.t'+\frac{1}{2} g.t'^2$

during the course of descend its initial vertical velocity is zero because it is at the top height, so $u_y'=0\ m.s^{-1}$

$21.4082=0+4.9t'^2$

$t'=2.09\ s$

Now the total time taken by the ball to hit the ground:

$t_t=t'+t$

$t_t=2.09+2.041$

$t_t=4.131\ s$

3 0

3 years ago

Because of the high sugar and caffeine content in energy drinks, disregarding the unpredictable risks, what are two other increa

Wittaler [7]

Answer:

It increases heart rate and blood pressure, heart problems, dehydration, seizures, and dangerously high blood pressure. (From overconsumption of caffine.)

Explanation:

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3 years ago

A 1-kilogram ball has 8 joules of kinetic energy.What is it speed?

scZoUnD [109]

K.E=0.5*mv²
v=square root 2ke/m
v= square root 2*8J/1 kg
v= 4 m/s

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3 years ago

Why are hydraulic brakes used?

mina [271]

Answer:

Hydraulic brake systems are used as the main braking system on almost all passenger vehicles and light trucks. Hydraulic brakes use brake fluid to transmit force when the brakes are applied.

Explanation:

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3 years ago